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ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-22
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The Banach inverse theorem for a small Lipschitz perturbation of the identity

Example

Assume the Axiom of Choice (The Axiom of Choice). Let X be a real Banach space (Banach space) and let g:XX be Lipschitz with constant q and 0q<1 (Lipschitz map, α-Hölder map for rational 0<α1, and contraction). Then F:=IX+g is bijective and its inverse is Lipschitz with constant at most (1q)1. If in addition g is of class Ck for some k1 (C k map between Banach spaces), then F is a global Ck diffeomorphism of X onto X.

Facts & Assumptions

Given: AC, a real Banach space X, a Lipschitz map g:XX with constant q[0,1), and F:=IX+g.

[L1]

Lipschitz with constant q: g(u)g(v)quv for all u,v (Lipschitz map, α-Hölder map for rational 0<α1, and contraction).

[L2]

A contraction of a nonempty complete metric space has a unique fixed point; a Banach space is a nonempty complete metric space (A contraction of a nonempty complete metric space into itself has exactly one fixed point, the limit of the iterates from any starting point, Banach space).

[L3]

Neumann: R<1 implies IR invertible with (IR)1(1R)1 (Neumann series and small perturbations of bounded inverses).

[L4]

A derivative is a norm limit of difference quotients, so a global Lipschitz constant q bounds the derivative by q wherever it exists (Fréchet derivative between Banach spaces, The operator norm as the least bound and as the unit-sphere or unit-ball supremum).

[L5]

Sum rule D(IX+g)(x)=IX+Dg(x), Ck-ness of IX+g for a Ck map g, and the inverse function theorem for Ck maps between Banach spaces, k1 (Chain sum product and composition rules for Banach derivatives, C k map between Banach spaces, Inverse function theorem for Banach spaces).

Verification

technique · direct
1.1

Fix yX and put Ty(x):=yg(x). Then Ty(x)Ty(x)=g(x)g(x)qxx by [L1], so Ty is a contraction of the nonempty complete metric space X; by [L2] it has exactly one fixed point, and x=Ty(x) is equivalent to F(x)=y.

L1L2
2.1

Consequently F is bijective with F1(y) the unique fixed point of Ty for each y. If xi:=F1(yi) for i=1,2, then x1x2=(y1y2)(g(x1)g(x2))y1y2+qx1x2, hence F1(y1)F1(y2)(1q)1y1y2 because 1q>0.

step 1.1L1algebra
2.2

Now assume g is of class Ck with k1; then F is of class Ck and DF(x)=IX+Dg(x) by [L5]. The derivative of g satisfies Dg(x)q by [L4], so Dg(x)q<1 and [L3] makes DF(x)=IX(Dg(x)) invertible with DF(x)1(1q)1 at every x.

step 1.1L3L4L5algebra
3.1

By the inverse function theorem [L5] applied at each x, and using that F is a bijection by [step 2.1], the global inverse F1 agrees near each y with the Ck local inverse of F; being locally of class Ck, F1 is of class Ck. Hence F is a global Ck diffeomorphism.

step 2.1step 2.2L5algebra
4.1

Steps 2.1, 2.2 and 3.1 prove all the assertions of the example.

step 2.1step 2.2step 3.1

Depends on

Used by

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