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The coinvariant algebra of S_3 as the Soergel bimodule of the longest element

Example

Take n=3 and let w0=s1s2s1 be the longest element of S3. Then Bw0=S⊗SS3S(3) and its reduced module is C(3), where C=S/(S+S3) is the unshifted coinvariant algebra: C has the Poincare polynomial 1+2t2+2t4+t6, so dim⁡C=6, and in the centered grading dim⁡(Bw0‾)−3=dim⁡(Bw0‾)3=1,dim⁡(Bw0‾)−1=dim⁡(Bw0‾)1=2. The standard-basis expansion of the Kazhdan-Lusztig basis element is H‾w0=Hw0+v(Hs1s2+Hs2s1)+v2(Hs1+Hs2)+v3, obtained by solving the bar-invariance and triangularity conditions with coefficients in vdZ[v−2]; its coefficients are non-negative, its value at v=1 sums to 6=dim⁡C, and it agrees with the rank-one and rank-two Kazhdan-Lusztig data Pe,w0=Psi,w0=Pw,w0=1 for ℓ(w)=2. Hence ch⁡(Bw0)=H‾w0: Soergel's conjecture holds for the longest element of S3, and the Δ-multiplicities of the coinvariant bimodule are the six coefficients just displayed, one for each element of S3.

Verification

technique · direct; the identification with the invariants-tensor bimodule, an explicit bar-invariance computation in the Hecke algebra, and the comparison of the graded dimensions

Given: S=R[x1,x2,x3] with deg⁡xi=2, the longest element w0=s1s2s1, the rank-two longest bimodule Bi,i+1,i=R⊗RWi,i+1R(3) (The rank-two longest type-A Soergel bimodule), the reduced module and the character (The reduced Soergel module and the dominant Lefschetz operator, Standard graph bimodules, support filtrations and characters), the normalized Hecke algebra with Hs2=1+(v−1−v)Hs and the Kazhdan-Lusztig basis (Existence and uniqueness of the Kazhdan–Lusztig basis), and multiplicativity of the standard character (The type-A standard character is multiplicative).

[F1] The rank-two longest bimodule is S⊗SS3S(3) after real scalar extension, and right reduction is tensoring with S/S+=R (The rank-two longest type-A Soergel bimodule, The reduced Soergel module and the dominant Lefschetz operator). The symmetric-polynomial and quotient-basis computations needed here are supplied in step 1.1; no general invariant-ring theorem is assumed.

[F2] In the Hecke algebra Hs−1=Hs+(v−v−1) for every simple s, and the bar involution acts on the standard basis by Hw‾=Hw−1−1; the Kazhdan-Lusztig basis is the unique basis of elements H‾w=Hw+∑y<wpy,wHy with py,w∈vZ[v] and H‾w‾=H‾w (Existence and uniqueness of the Kazhdan–Lusztig basis).

[F3] The coefficient of Hy in ch⁡(M) is ∑d(M:Δy(d))vd with non-negative integral multiplicities, and for the standard layer Δy(d) the reduced dimension sits in degree ℓ(y)−d; hence the multiset of monomials of the character, read with the degrees ℓ(y)−d, is the graded dimension of the reduced module (Standard graph bimodules, support filtrations and characters).

[F4] The character is multiplicative with simple value Hs+v, and the rank-two decomposition is Bs1Bs2Bs1≅Bw0⊕Bs1 (The type-A standard character is multiplicative, Rank-two type-A Soergel bimodule decompositions).

1.1givenF1

The bimodule and its reduction. Symmetric polynomials in three variables are generated by e1,e2,e3: for a homogeneous symmetric polynomial, its lexicographically leading monomial has exponents a≥b≥c; subtracting its coefficient times e1a−be2b−ce3c lowers that leading monomial. The finite set of monomials of the fixed total degree makes this reduction terminate. Thus SS3=R[e1,e2,e3] and [F1] gives the reduced module C(3) with C=S/(e1,e2,e3). Eliminating x3=−x−y gives C=R[x,y]/(x3,y2+xy+x2): the e3 relation is x2y+xy2=0, and subtracting this from x(x2+xy+y2)=0 gives x3=0, with the same identities proving the reverse inclusion of ideals. Over R[x]/(x3), division by the monic quadratic in y gives the free basis 1,y; hence 1,x,y,x2,xy,x2y is a real basis and the dimensions are 1,2,2,1 in degrees 0,2,4,6, centered at −3,−1,1,3 after shifting by (3). The tensor bimodule is generated as a bimodule by 1⊗1 and its bottom component is one dimensional, so every degree-zero endomorphism is scalar; it is therefore indecomposable. The balanced surjection f⊗g↦fw0(g) onto Sw0 proves that it has the w0 graph in its support. In the rank-two decomposition it is the summand carrying the w0 graph (the other summand Bs1 has only the e,s1 graphs), so its label is w0.

1.2givenF2algebra

The Kazhdan-Lusztig element. Put A:=v−v−1 and J:=Hw0+v(Hs1s2+Hs2s1)+v2(Hs1+Hs2)+v3. The element J lies in Hw0+∑y<w0vZ[v]Hy, since all coefficients belong to vZ[v]. For bar-invariance we expand: from Hs−1=Hs+A and the reduced products Hs1Hs2=Hs1s2 and Hs1s2Hs1=Hw0 one computes Hs1s2‾=Hs1s2+A(Hs1+Hs2)+A2 and Hw0‾=Hw0+A(Hs1s2+Hs2s1)+A2(Hs1+Hs2)+A+A3, while Hs1‾=Hs1+A and Hs2‾=Hs2+A. Applying the semilinear involution to J gives J‾=Hw0‾+v−1(Hs1s2‾+Hs2s1‾)+v−2(Hs1‾+Hs2‾)+v−3; collecting coefficients in the standard basis, the coefficient of Hs1s2+Hs2s1 becomes A+v−1=v, the coefficient of Hs1+Hs2 becomes A2+2v−1A+v−2=v2, and the coefficient of He becomes A+A3+2v−1A2+2v−2A+v−3=v3. Hence J‾=J, and by the uniqueness clause of [F2] J=H‾w0.

2.1step 1.1step 1.2F3F4∎

Character and multiplicities. By [F4], ch⁡(Bw0)=(Hs1+v)(Hs2+v)(Hs1+v)−(Hs1+v)=J, the last equality following by the quadratic relation Hs2=1+(v−1−v)Hs and reduced multiplication. Step 1.2 gives J=H‾w0, so the Δ-multiplicities of Bw0 are exactly the six coefficients of J, one for each of the six elements of S3. Reading them through [F3], the layer Δw0(0) contributes in degree ℓ(w0)=3, the two layers Δs1s2(1),Δs2s1(1) contribute in degree 1 with multiplicity two, the two layers Δs1(2),Δs2(2) contribute in degree −1 with multiplicity two and the layer Δe(3) contributes in degree −3; this is the graded dimension 1,2,2,1 of the centered coinvariant algebra computed in step 1.1, and the value at v=1 is 6=dim⁡C. The coefficients Pe,w0=Psi,w0=Ps1s2,w0=Ps2s1,w0=1 are the classical normalization of these coefficients. This verifies the example.

Remarks

  • The two computations are independent: the bar-invariance determines the Kazhdan-Lusztig element from the Hecke algebra alone, and the graded dimensions of the coinvariant algebra come from the invariant theory; their agreement is the content of Soergel's conjecture at w0.
  • The example is an illustration of the character theorem, not a supplier of it; the base of the simultaneous induction is computed on the axiom page and does not use this page.

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