Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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The commutator pairings of Dih(C4) and Q8 are the same, while the groups are not isomorphic

Example

The commutator pairings of Dih(C4) and Q8 are the same, while the groups are not isomorphic.

Facts & Assumptions

Given: The objects and hypotheses in the Example.

[F1]

For an extraspecial p-group P with Z(P)=z, the commutator pairing is the map bz(xˉ,yˉ)Z/p determined by [x,y]=zbz(xˉ,yˉ) (The commutator pairing of an extraspecial p-group relative to a chosen generator of its centre).

[L1]

The commutator pairing is independent of the coset representatives, is Fp-bilinear on P/Z(P), and is alternating (The commutator pairing is well defined on the central quotient, is bilinear over Fp, and is alternating).

[L2]

The generalized dihedral group Dih(C4) and the quaternion group Q8 are extraspecial of order 8, with six and two solutions of x2=1 respectively (Dih(C4) and Q8 are extraspecial of order 8, with six and two solutions of x2=1 respectively).

[L4]

Q8  :=  {1,1,i,i,j,j,k,k}    H×. (The quaternion group Q8={±1,±i,±j,±k} inside the nonzero quaternions).

[L5]

The order of a finite group. Let G be a group whose underlying set is finite, so that Gn for some nN. (The order G of a finite group and the order ord(g) of an element, with ord(g)= when no positive power of g is the identity).

Verification

technique · direct
1.1

In Dih(C4) the images of r and s form a basis of the central quotient and [r,s]=r2, so the pairing sends that basis pair to 1.

F1L1L2L3algebra
2.1

In Q8 the images of i and j form a basis and [i,j]=1, so the pairing again sends that basis pair to 1; the two pairings agree in these coordinates.

F1L4step 1.1algebra
3.1

The groups are nevertheless not isomorphic, because six elements satisfy x2=1 in the first and two in the second.

L2L5step 2.1

Depends on

Used by

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Sources