Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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The Heisenberg group of order 27 has exponent 3 and thirteen subgroups of order 3

Example

The Heisenberg group of order 27 has exponent 3 and thirteen subgroups of order 3.

Facts & Assumptions

Given: The objects and hypotheses in the Example.

[F1]

The Heisenberg group of order p3 is the set (Z/p)3 with (a,b,c)(a,b,c)=(a+a,b+b,c+c+ab) (The Heisenberg group of order p3 over Z/p).

[L1]

The Heisenberg multiplication makes (Z/p)3 a nonabelian group of order p3 (The Heisenberg multiplication is a group law, nonabelian, on a set of p3 elements).

[L2]

The Heisenberg group of order p3 is extraspecial, and for odd p it has exponent p (The Heisenberg group of order p3 is extraspecial, and for odd p it has exponent p).

[L3]

For a finite group G, its exponent is exp(G)=min{nN:n>0 and gn=e for every gG}. The set is nonempty by, and gives its least member; powers use. (The exponent of a finite group).

[L4]

The order of a finite group. Let G be a group whose underlying set is finite, so that Gn for some nN. (The order G of a finite group and the order ord(g) of an element, with ord(g)= when no positive power of g is the identity).

Verification

technique · direct
1.1

Instantiate the multiplication at p=3 to obtain a nonabelian group of order twenty-seven.

F1L1
1.2

Every nonidentity element cubes to the identity, since three is odd and the general exponent statement applies.

L2L3
2.1

The twenty-six nonidentity elements therefore fall into thirteen subgroups of order three, each containing two of them.

L4L5step 1.2algebra

Depends on

Used by

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Sources