Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedprecheck passaudited 2026-08-26
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The Heisenberg group of order 27 has exponent 3 and thirteen subgroups of order 3

Example

The Heisenberg group of order 27 has exponent 3 and thirteen subgroups of order 3.

Facts & Assumptions

Given: The objects and hypotheses in the Example.

[F1]

The Heisenberg group of order p3 is the set (Z/p)3 with (a,b,c)(a′,b′,c′)=(a+a′,b+b′,c+c′+ab′) (The Heisenberg group of order p3 over Z/p).

[L1]

The Heisenberg multiplication makes (Z/p)3 a nonabelian group of order p3 (The Heisenberg multiplication is a group law, nonabelian, on a set of p3 elements).

[L2]

The Heisenberg group of order p3 is extraspecial, and for odd p it has exponent p (The Heisenberg group of order p3 is extraspecial, and for odd p it has exponent p).

[L3]

For a finite group G, its exponent is exp⁡(G)=min⁡{n∈N:n>0 and gn=e for every g∈G}. The set is nonempty by, and gives its least member; powers use. (The exponent of a finite group).

[L4]

The order of a finite group. Let G be a group whose underlying set is finite, so that G≈n for some n∈N. (The order ∣G∣ of a finite group and the order ord⁡(g) of an element, with ord⁡(g)=∞ when no positive power of g is the identity).

Verification

technique · direct
1.1F1L1

Instantiate the multiplication at p=3 to obtain a nonabelian group of order twenty-seven.

1.2L2L3

Every nonidentity element cubes to the identity, since three is odd and the general exponent statement applies.

2.1L4L5step 1.2algebra∎

The twenty-six nonidentity elements therefore fall into thirteen subgroups of order three, each containing two of them.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources