Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01 rests on unproved material (inherited)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Rests on 3 statements not proved in this library, by way of the results it cites. This item cites no such statement directly; it depends on results that do. The unproved premises it inherits are Cohen's first model: an infinite Dedekind-finite set of reals, Sierpiński 1947: the generalised continuum hypothesis implies the Axiom of Choice and The continuum hypothesis and its generalisation are independent of ZFC. Each is recorded with a citation to the literature and is not established here, because the track that would prove it has not yet been developed in this library. Everything else in this proof is proved here.

The connecting map for a short exact sequence of two-term complexes

Example

Fix a nonzero integer m. Consider the chain map ×m:Z[0]Z[0] and its canonical short exact cone sequence 0Z[0]Cone(×m)Z[1]0. The middle term is a two-term complex, and its connecting morphism 1:H1(Z[1])H0(Z[0]) is multiplication by m.

Facts & Assumptions

Given: A nonzero integer m.

[L1]

In module categories, the connecting map is computed by lifting a cycle and taking the boundary of the lift (Elementwise formula for the connecting map in module categories).

Verification

technique · direct
1.1

A class in H1(Z[1]) is represented by an integer xZ=C0. In the cone sequence, (0,x) is a lift of that cycle to degree 1 of Cone(×m).

L1givenconstruct
2.1

The cone differential sends (0,x) to (mx,0). Therefore [L1] gives 1([x])=[mx]H0(Z[0])=Z. So the connecting morphism is multiplication by m.

L1step 1.1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources