Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The functional f01/2f on Lp[0,1] has norm 21/q

Example

Assume the Axiom of Countable Choice (The Axiom of Countable Choice (ACω)).

Let 1p< and let q be conjugate to p. On [0,1] with Lebesgue measure, define Λ([f]):=01/2f(x)dx. Then Λ is a bounded linear functional on Lp[0,1] and Λ=21/q, with the endpoint convention 21/=1 when p=1.

Facts & Assumptions

Given: The Axiom of Countable Choice and an exponent 1p< with conjugate exponent q.

[L2]

If gLq(μ), then the pairing functional Λg has norm gq in the ranges treated on the A page (The functional Λg has norm gq; for q= assume μ is semifinite).

Verification

technique · Represent the functional by the indicator of $[0,1/2]$, compute that indicator's $L^q$ norm from its measure, and invoke the norm formula for $\Lambda_g$
1.1

Let g:=1[0,1/2]. [given, construct] Then Λ([f])=01f(x)g(x)dx=Λg([f]), so Λ is exactly the pairing functional associated to g.

givenconstruct
1.2

By [L1], if q< then gqq=01gqdx=01/21dx=12, so gq=21/q.

L1given
1.3

If q=, then g1 everywhere and g=1 on a set of positive measure, so g=1=21/.

L1given
2.1

Applying [L2] to step 1.1 and steps 1.2-1.3 gives Λ=Λg=gq=21/q.

L2step 1.1step 1.2step 1.3

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

26 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources