Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-10
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The hyperbolic upper half space metric

Example

For n≥1, on {(x1,…,xn−1,y):y>0} the metric g=y−2(∑i<ndxi2+dy2) has density y−n∣dx1⋯dxn−1dy∣.

Facts & Assumptions

Given: The upper half-space with its Euclidean open-subset smooth structure.

[F1]

Coordinate criterion for a riemannian metric: A tensor g=∑i,jgij dxi⊗dxj is Riemannian exactly when its coordinate matrix G=(gij) has smooth entries and is symmetric positive definite. Under J=∂x/∂y it transforms by Gy=JTGxJ.

[F2]

Riemannian volume density: The Riemannian volume density is μg=det⁡Gx ∣dx1⋯dxn∣ in coordinates. The matrix is that of prop-coordinate-criterion-for-a-riemannian-metric, so its determinant is positive and smooth. The density frames and their absolute-Jacobian law are def-density-bundle-and-smooth-density. In dimension zero take the empty determinant to be one, giving weight one at every point, independently of orientation. The compatibility of these local formulas is proved in lem-the-riemannian-volume-density-is-coordinate-independent.

Verification

technique · direct
1.1F1given

For y>0, y−2 is smooth and positive. Hence G=y−2In is a smooth symmetric positive-definite matrix, since vTGv=y−2∑ivi2>0 when v≠0. It defines a Riemannian metric.

2.1F2step 1.1∎

Its determinant is y−2n and the positive square root is y−n. The density definition therefore gives the asserted formula. At (0,…,0,2) the matrix is 14In and the density coefficient is 2−n.

Source locator

Lee, p.328, coordinate positive-definiteness criterion; Proposition 15.31, p.390, volume coefficient; pp.430–431, Riemannian density. The upper-half-space coefficients are computed above; no curvature or completeness statement is asserted.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources