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ExampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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The two extraspecial groups of order 32 have 20 and 12 solutions of x2=1

Example

The two extraspecial groups of order 32 have 20 and 12 solutions of x2=1.

Facts & Assumptions

Given: The objects and hypotheses in the Example.

[L1]

The generalized dihedral group Dih(C4) and the quaternion group Q8 are extraspecial of order 8, with six and two solutions of x2=1 respectively (Dih(C4) and Q8 are extraspecial of order 8, with six and two solutions of x2=1 respectively).

[L2]

If P1 and P2 are extraspecial 2-groups with ti solutions of x2=1, then P1P2 has (t1t2+(P1t1)(P2t2))/2 such solutions (A product formula for the number of square roots of the identity in a central product of extraspecial 2-groups).

[L3]

Q8Q8Dih(C4)Dih(C4) (Q8Q8Dih(C4)Dih(C4)).

[L4]

For each n1 there are exactly two extraspecial groups of order 21+2n up to isomorphism, with 22n+2n and 22n2n solutions of x2=1 (For each n1 there are exactly two extraspecial groups of order 21+2n).

[L5]

The order of a finite group. Let G be a group whose underlying set is finite, so that Gn for some nN. (The order G of a finite group and the order ord(g) of an element, with ord(g)= when no positive power of g is the identity).

[L6]

A set A is finite when An for some nN. (The cardinality A of a finite set).

[L7]

A central product of extraspecial 2-groups identified along their centres is extraspecial and has order E1E2/2 (A central product of extraspecial p-groups identified along their centres is extraspecial).

Verification

technique · direct
1.1

The two factors have eight elements each, with six and two solutions of x2=1 respectively; each central product below is extraspecial of order 88/2=32.

L1L5L7
2.1

For two dihedral factors the formula gives (36+4)/2=20, and for a dihedral and a quaternion factor it gives (12+12)/2=12.

L2L6step 1.1algebra
3.1

These are the values 24+22 and 2422 predicted by the classification, and the two central products with two quaternion factors and with two dihedral factors give the same group.

L2L3L4step 2.1

Depends on

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