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A product formula for the number of square roots of the identity in a central product of extraspecial 2-groups

Statement

Let P1 and P2 be extraspecial 2-groups and let P=P1αP2 be the central product along an isomorphism α of their centres. Write t(G)={gG:g2=1}. Then

t(P)=t(P1)t(P2)+(P1t(P1))(P2t(P2))2.

Facts & Assumptions

Given: Extraspecial 2-groups P1,P2 with Z(Pi)=zi of order two, an isomorphism α:Z(P1)Z(P2), and P=P1αP2 with quotient map π:P1×P2P.

[F1]

For groups G,H with central subgroups Z1Z(G), Z2Z(H) and an isomorphism α:Z1Z2, the central product GαH is the quotient of G×H by N={(z,α(z)1):zZ1} (The central product GαH of two groups along an isomorphism of central subgroups).

[F2]

The external direct product G×H carries the componentwise operation (The external direct product G×H with componentwise multiplication).

[F3]

The quotient group G/N has the left cosets gN as elements, with product (gN)(hN):=ghN (The quotient group G/N and coset product (gN)(hN)=ghN).

[F4]

Z(G):={zG:zg=gz for every gG} (The center Z(G) of a group).

[L1]

For a finite p-group P the following are equivalent: P is extraspecial; P is nonabelian, Z(P)=p and P/Z(P) is elementary abelian; P is nonabelian and Z(P)=P=Φ(P) has order p (Three equivalent descriptions of an extraspecial p-group).

[L2]

An elementary abelian p-group is a finite abelian p-group in which every nonidentity element has order p (Elementary abelian p-groups).

[L3]

The subgroup N={(z,α(z)1):zZ1} of G×H is central, hence normal (The identified subgroup used to form a central product is central, hence normal).

[L4]

The canonical maps into a central product are injective homomorphisms whose images commute elementwise, generate the product, and meet in the image of the identified subgroup (The two canonical maps into a central product are injective homomorphisms whose images commute, generate it, and meet in the identified centre).

[L5]

For a finite group G and HG, G=[G:H]H (Lagrange's theorem: G=[G:H]H for every subgroup H of a finite group G).

[L6]

A is the unique natural number n with An (The cardinality A of a finite set).

Proof

technique · direct
1.1

Since Pi/Z(Pi) is elementary abelian, g2Z(Pi)={1,zi} for every gPi; so Pi splits into the t(Pi) elements with g2=1 and the Pit(Pi) elements with g2=zi.

F4L1L2
1.2

The quotient map π is surjective with kernel N={(z,α(z)1):zZ(P1)}, which has two elements, so every element of P has exactly two preimages in P1×P2.

F1F3L3L5L6
1.3

Because the two canonical images commute, π(g,h)2=π(g2,h2) for all gP1 and hP2.

F2F3L4
2.1

Hence π(g,h)2=1 exactly when (g2,h2)N, that is exactly when g2=1 and h2=1, or g2=z1 and h2=α(z1)1=z2.

F1F4step 1.1step 1.3
3.1

The number of pairs (g,h) with π(g,h)2=1 is therefore t(P1)t(P2)+(P1t(P1))(P2t(P2)).

L6step 1.1step 2.1
4.1

Each element of P with square the identity is counted exactly twice in that total, so t(P) is half of it, which is the displayed formula.

L6step 1.2step 3.1

Remarks

The second summand is what makes the formula more than a product: an element of P can square to the identity because both of its coordinates square to the identity, or because both square to the identified central element and those two squares cancel in the quotient.

Writing Pi=21+2ni and t(Pi)=22ni+εi2ni with εi=±1, the formula collapses to t(P)=22n+ε1ε22n with n=n1+n2: the signs multiply.

Depends on

Used by

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Sources