Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Deterministic zero-reward arms have zero regret

Example

Fix any horizon n≥1 and take two arms with deterministic reward stacks Xs,1=Xs,2=0 for every s∈[n]. Then μ1=μ2=μ∗=0 and Δ1=Δ2=0. Every admissible policy has identically zero pseudo-regret and realized reward regret, so both expected regrets are zero.

Example references

Finite stochastic bandit model, gaps, and regret: the finite-arm means, gaps, pseudo-regret, and realized reward regret used in the example.

Facts & Assumptions

Given: The two-arm deterministic reward table in the example and the definitions of gaps and the two regret quantities.

[F1]

The arm means, gaps, pseudo-regret, and realized reward regret are those in the finite stochastic bandit model (Finite stochastic bandit model, gaps, and regret).

Verification

1.1givenF1algebra

Each arm's law is the point mass at 0, so both finite means equal 0. Hence μ∗=0 and Δ1=Δ2=0.

2.1givenF1step 1.1algebra

For every policy and every round, μ∗−μAt=0 and the observed reward Yt=0. The defining sums therefore give Rˉn=0 and Rnrew=0 pointwise.

3.1givenstep 2.1algebra∎

Taking expectations of the two identically zero random variables shows that expected pseudo-regret and expected reward regret both equal zero.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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