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The two-dimensional five-point Poisson matrix under nested dissection

Example

For k≥1, let Gk be the grid on coordinate vertices {0,…,k−1}2, relabeled by the lexicographic zero-based bijection in Recursive coordinate-separator ordering for two- and three-dimensional grids, and let Ak=4I−Adj⁡(Gk), the Dirichlet five-point Poisson matrix. The coordinate nested-dissection ordering recursively places its median row and column after the child rectangles. This example checks positive definiteness and instantiates the two-dimensional factorization bounds.

Facts & Assumptions

Given: An integer k≥1, the k×k nearest-neighbor grid Gk, and Ak=4I−Adj⁡(Gk).

[F1]

Recursive coordinate-separator ordering for two- and three-dimensional grids: In dimension two the procedure orders child rectangles first and then appends the union of the selected median row and median column.

[F2]

Nested dissection gives the stated work and factor-storage bounds on regular grids: For a symmetric positive-definite matrix with this grid pattern and k≥2, exact scalar multifrontal Cholesky under the stated ordering uses O(n3/2) arithmetic work and O(nlog⁡n) symbolic factor storage for n=k2. Storage counts allocated factor entries, including structural zeros, and excludes temporary contribution arrays. For k=1, both costs are O(1).

Verification

1.1givenalgebra

For every grid vertex v, let b(v)=4−deg⁡Gk(v) be its number of missing boundary neighbors. Expanding squares gives xTAkx=∑{v,w}∈E(Gk)(xv−xw)2+∑v∈Gkb(v)xv2. The right side is nonnegative. If it is zero, every adjacent pair has equal coordinates and every boundary vertex with b(v)>0 has value zero. The grid is connected and has a boundary vertex, so all coordinates are equal to zero. Hence Ak is positive definite.

2.1step 1.1F1F2algebra

By [F1], the order is the coordinate nested-dissection order on the five-point grid. The matrix is symmetric positive definite by step 1.1 and its off-diagonal pattern is exactly Gk. For k≥2, applying [F2] with n=k2 to exact scalar multifrontal Cholesky gives arithmetic work O((k2)3/2)=O(k3) and symbolic factor storage O(k2log⁡(k2))=O(k2log⁡k), with the allocation convention of [F2]. For k=1, the matrix and factor each have one entry.

3.1step 1.1step 2.1∎

Step 1.1 verifies the matrix hypothesis and step 2.1 gives the nested-dissection cost specialization.

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