Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The word metrics of Z for {1} and for {2,3} differ at 1 and are bilipschitz equivalent

Example

The word metrics of Z for {1} and for {2,3} differ at 1 and are bilipschitz equivalent.

Facts & Assumptions

Given: The objects and hypotheses in the Example.

[F1]

The word length gS is the least n such that g is a product of n elements of SS1 (Word length of a group element with respect to a generating set).

[L1]

The word metric of G with respect to S is dS(g,h)=g1hS (The word metric of a group with respect to a generating set).

[L2]

The identity map between the word metrics of two finite generating sets of a group is a bilipschitz equivalence (The identity map between the word metrics of two finite generating sets is a bilipschitz equivalence).

[L3]

A map is a bilipschitz embedding when c1d(x,x)d(f(x),f(x))cd(x,x) for some c>0, and a bilipschitz equivalence when it is a bijective such map with bilipschitz inverse (Bilipschitz embeddings and bilipschitz equivalences of metric spaces).

[L4]
  • d and d are topologically equivalent if they have the same metric topology: Td=Td. - d and d are uniformly equivalent if for every real ε>0 there are reals δ>0 and δ>0 such that, for all x,yX, d(x,y)<δ    d(x,y)<εandd(x,y)<δ    d(x,y)<ε. - d and d are Lipschitz equivalent if there are reals α,β>0 with αd(x,y)    d(x,y)    βd(x,y)for all x,yX. (Topologically, uniformly and Lipschitz equivalent metrics on a set).

Verification

technique · direct
1.1

For S={1} the length of 1 is one, while for S={2,3} the element 1 is not a one-letter word in SS1={±2,±3} and satisfies 1=3+(2), so its length is two. Thus the two metrics already differ at the pair (0,1).

F1L1algebra
2.1

The comparison theorem gives constants: every member of one symmetrised set has length at most three in the other, so the identity is bilipschitz with constant three.

L1L2L3L4step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

18 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources