Alphabeta Math
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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Two Gaussian weights are the squared norms of the two cardinal polynomials

Example

Let (a,b,2,3,μ) be Gaussian moment data, with distinct Gaussian nodes x1<x2 and weights w1,w2. Its cardinal polynomials are ℓ1(X)=X−x2x1−x2,ℓ2(X)=X−x1x2−x1. The degree-three exactness theorem implies w1=∫ℓ12 dμ=μ2−2x2μ1+x22μ0(x1−x2)2>0,w2=∫ℓ22 dμ=μ2−2x1μ1+x12μ0(x2−x1)2>0, where μj=∫xj dμ for j=0,1,2.

Facts & Assumptions

Given: Moment data of order 3, its two-node Gaussian rule, and its distinct nodes x1,x2.

[F1]

The m-node Gaussian quadrature rule for a positive measure: wi=∫ℓi dμ and Q2(f)=w1f(x1)+w2f(x2).

[F2]

Gaussian quadrature is exact through degree 2m−1 and has positive weights: the rule is exact through degree 3 and wi>0.

[F3]

Cardinal-polynomial interpolation and Cardinal interpolation functions are polynomials of the stated degrees: the displayed ℓi are degree one and satisfy ℓi(xk)=1 for k=i and 0 otherwise.

[F4]

Positive-measure Gaussian quadrature moment data and The Lebesgue integral is linear on L1(μ): for j=0,1,2, ∫xj dμ=μj, and integration distributes over the finite polynomial expansion.

Proof

1.1F1F2F3

Since deg⁡(ℓi2)=2, exactness [F2] gives Q2(ℓi2)=∫ℓi2 dμ. Expanding the finite rule sum [F1] and using the cardinal values [F3] gives Q2(ℓi2)=wi, hence ∫ℓi2 dμ=wi.

2.1F2F4step 1.1algebra∎

The formula for ℓ1 gives ℓ1(x)2=(x2−2x2x+x22)/(x1−x2)2. Integrating term by term using [F4] proves the displayed expression for w1. Replacing the omitted node x2 by x1 gives the displayed expression for w2. Their strict positivity is [F2].

Depends on

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