Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Weighted norm of an interval indicator

Example

Assume the Axiom of Countable Choice (The Axiom of Countable Choice (ACω)).

Let n=1, let 1<p<∞, let −1<α<p−1 and let r>0. For the admissible power weight w(x)=∣x∣α one has ∥1(0,r)∥Lp(w)=(rα+1α+1)1/p, which tends to 0 as r→0+ and grows like r(α+1)/p as r→∞. At the endpoint α=−1 the integral ∫0rx−1dx diverges logarithmically for every r>0, and for each fixed r>0 the displayed norm diverges as α↓−1.

Facts & Assumptions

Given: Countable Choice; 1<p<∞, −1<α<p−1, r>0, and w(x)=∣x∣α on R.

[F1]

∥f∥Lp(w)p=∫R∣f∣pw dλ and Lp(w) is the corresponding space of classes (Weights, their associated measures, and the spaces L^p(w)); the weight ∣x∣α is admissible for α>−1 and lies in Ap for −1<α<p−1 (The A_p range of a power weight, Muckenhoupt A_p and A_1 weights).

[F2]

For α>−1 the power function has antiderivative tα+1/(α+1) on (0,∞), and ∫0rt−1dt=+∞ for every r>0, the divergence being logarithmic (Continuity and derivatives of positive-base real powers, The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t, Comparison tests for improper integrals).

Verification

technique · direct
1.1F1F2givenalgebra

Direct computation: ∥1(0,r)∥Lp(w)p=∫0r∣x∣αdx=∫0rxαdx=rα+1/(α+1) for α>−1 by [F2], since ∣x∣=x on (0,r); taking p-th roots gives the displayed formula.

2.1F2step 1.1givenalgebra∎

As r→0+ the expression (rα+1/(α+1))1/p tends to 0 because α+1>0; as r→∞ it grows like the constant multiple r(α+1)/p of the power function. At α=−1 one has ∫0rx−1dx=+∞ by [F2], so for fixed r>0 the full expression (rα+1/(α+1))1/p diverges as α↓−1, since rα+1→1. The density ∣x∣−1 does not satisfy this page's local-integrability definition of a weight; its integral of the indicator is nevertheless well defined and infinite.

Depends on

Used by

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Dependency tree · two levels

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Sources