Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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x5−2 over Q is solvable by radicals although it is a quintic

Example

The quintic polynomial x5−2 over Q is solvable by radicals. Its splitting field is contained in

Q(ζ5,25),

so it lies in a radical extension of Q.

Facts & Assumptions

Given: The polynomial f(x)=x5−2.

[F1]

A polynomial is solvable by radicals when its splitting field lies in a radical extension (A polynomial is solvable by radicals when its splitting field lies in a radical extension).

[L1]

A splitting field is generated by all roots of the polynomial (Polynomials that split and splitting fields of a polynomial or a family of polynomials).

Verification

technique · direct
1.1L1

The five roots of x5−2 are 25, ζ525, ζ5225, ζ5325, ζ5425. Therefore [L1] makes the splitting field a subfield of Q(ζ5,25).

2.1F1step 1.1∎

The field Q(ζ5,25) is radical over Q: first adjoin ζ5, a root of x5−1, and then adjoin 25, a root of x5−2. Hence [F1] says that x5−2 is solvable by radicals.

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources