Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passverified 2026-09-24 (gpt-6-sol)
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The special-value formula gives ζ(4)=π4/90

Example

ζ(4)=π490.

Facts & Assumptions

Given: The Bernoulli generating function and the cotangent expansion.

[L1]

Bernoulli numbers are defined by tet−1=∑n≥0Bnn!tn (The Bernoulli numbers are defined by the generating series t/(et−1)).

[L2]

The cotangent expansion is πcot⁡(πz)=1/z+∑n≥12z/(z2−n2) (The Mittag-Leffler expansion of pi cotangent).

[L3]

For Re⁡s>1, ζ(s)=∑n≥1n−s (The Riemann zeta function on the half-plane Re⁡s>1).

Verification

technique · direct
1.1L1givenalgebra

Expanding et−1=t+t2/2+t3/6+t4/24+⋯ and solving for the quotient in [L1] gives tet−1=1−t2+t212−t4720+⋯ , so B4=−1/30.

2.1step 1.1L1L2L3algebra∎

For ∣z∣<1, expand each term of [L2] into an absolutely locally convergent geometric series and use [L3]. The coefficient of z4 in πzcot⁡(πz) is then −2∑n≥1n−4=−2ζ(4). On the other hand, setting t=2πiz in [L1] gives πzcot⁡(πz)=t/(et−1)+t/2; the coefficient of z4 is B4(2πi)4/4!=−π4/45 by step 1.1. Equating these coefficients yields ζ(4)=π4/90.

Depends on

Used by

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Dependency tree · two levels

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Sources