Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-31
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FALSE: every uniformizable topology has a unique compatible uniformity

Statement

FALSE. Every uniformizable topology has a unique compatible uniformity.

Facts & Assumptions

Given: The usual topology and usual metric uniformity U\mathcal U on R\mathbb R.

[L1]

The map h(x)=x/(1+x)h(x)=x/(1+|x|) is a homeomorphism R(1,1)\mathbb R\to(-1,1) but not a uniform isomorphism for the usual metric uniformities (The map xx/(1+x)x\mapsto x/(1+|x|) is a uniformly continuous homeomorphism from R\mathbb{R} to (1,1)(-1,1) whose inverse is not uniformly continuous).

[L2]

Uniformizable means induced by a uniformity, and a uniform isomorphism has uniformly continuous inverse (Uniformizable and separated-uniformizable topological spaces, Uniform embedding and uniform isomorphism).

Refutation

technique · direct
1.1

Pull the usual uniformity of (1,1)(-1,1) back along the homeomorphism hh, obtaining a uniformity V\mathcal V on the underlying set R\mathbb R.

L1
2.1

Since hh is a homeomorphism, V\mathcal V induces the usual topology of R\mathbb R, so that topology is uniformizable.

step 1.1L2
2.2

If V=U\mathcal V=\mathcal U, then hh would be a uniform isomorphism from U\mathcal U onto the usual uniformity of (1,1)(-1,1), contrary to [L1].

step 1.1L1L2
3.1

Thus one topology has distinct compatible uniformities, refuting the statement.

step 2.1step 2.2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 37 results over 12 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources