Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passverified 2026-08-04 (gpt-5.6-sol-codex-subscription)
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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FALSE: a connected simple graph in which every vertex has even degree must itself be a cycle

Statement

FALSE. Every connected finite simple graph in which every vertex has even degree is a cycle graph.

Facts & Assumptions

Given: The bowtie graph with vertices x,a,b,c,dx,a,b,c,d and edges xa,ab,bx,xc,cd,dxxa,ab,bx,xc,cd,dx, consisting of two triangles that share only xx.

[F2]

A connected graph has a path between every two vertices (Connected graphs and connected components defined by the existence of vertex paths).

[F3]

In the cycle graph CnC_n each vertex is joined by an edge exactly to its predecessor and its successor modulo nn (Empty and complete graphs, complete bipartite graphs, and the convention that PnP_n and CnC_n have nn vertices); with [F1] this gives every vertex of a cycle graph exactly two neighbours.

Refutation

technique · direct
1.1

Every two vertices of the bowtie are joined by a path, using xx when they lie in different triangles, so the graph is connected by [F2].

givenF2
1.2

The vertex xx has neighbours a,b,c,da,b,c,d and hence degree 44; each other vertex has degree 22. Thus all degrees are even by [F1].

givenF1
2.1

The bowtie is not a cycle graph because its vertex xx has degree 44, whereas [F3] gives degree 22 at every vertex of a cycle graph. Steps 1.1 and 1.2 therefore refute the claim.

step 1.1step 1.2F3

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 17 results over 11 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources