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False statementConstruction: Literature-sourcedVerification: AI-adaptedprecheck passaudited 2026-09-04
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FALSE: every additive functor has L_0 naturally isomorphic to itself

Statement

Every additive functor F has L0F naturally isomorphic to F.

Facts & Assumptions

Given: The additive functor F(M)=Hom⁡Z(Z/2Z,M) on abelian groups, and supplied projective resolution data P on a class containing Z/2Z that assigns it the standard resolution below.

[L1]

If F is right exact, the zero-th left derived functor recovers F naturally (The zero-th left derived functor of a right exact functor recovers the functor).

[L2]

Left derived objects are computed from the homology of an applied deleted projective resolution (Left derived objects relative to supplied projective resolution data).

[L3]

Additivity means preservation of sums on hom-groups (Additive functor).

Refutation

technique · direct
1.1L2L3givenalgebra

The functor F is additive by [L3], but it is enough to compute its value on the standard projective resolution 0→Z→×2Z→Z/2Z→0. Applying F to the deleted resolution gives 0→Hom⁡Z(Z/2,Z)→×2Hom⁡Z(Z/2,Z)→0, and both displayed Hom groups are 0.

2.1L1step 1.1∎

Therefore L0PF(Z/2)=0, while F(Z/2)=Hom⁡Z(Z/2,Z/2)≠0. So L0PF is not naturally isomorphic to F for this supplied datum and additive functor. Thus additivity alone does not guarantee recovery; [L1] records right exactness as a sufficient hypothesis, and the displayed claim is false.

Depends on

Used by

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources