Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-29
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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FALSE: every complex class function with self-inner-product 1 is a character

Statement

The statement "every complex class function with self-inner-product 1 is a character" is false: for a nontrivial finite group G with trivial character 1, the class function 1 has self-inner-product 1 but is not a character.

Facts & Assumptions

Given: A finite cyclic group G of order n2, its trivial character 1, and the class function 1 defined by (1)(g)=1 for every g.

[F1]

The cyclic group of order n2 has the trivial irreducible character 1 with 1(g)=1 for every g (The character table of a finite cyclic group over C).

[F2]

A complex character is irreducible exactly when its self-inner-product is 1 (A complex character is irreducible if and only if its self-inner-product is 1).

[A1]

The inner product satisfies cφ,cψ=c2φ,ψ for a scalar c, so 1,1=1,1.

[A2]

Every character χ of a representation satisfies χ(1)=dimV0.

Refutation

technique · construct
1.1

The constant function 1 is a class function, because it is constant on G, hence constant on every conjugacy class.

given
1.2

By [F1] and [F2], the trivial character satisfies 1,1=1; by [A1], 1,1=1,1=1.

F1F2A1given
1.3

If 1 were a character of some representation, then by [A2] its value at 1 would be nonnegative, but (1)(1)=1<0. Hence 1 is not a character.

A2given
2.1

Steps 1.1 through 1.3 exhibit a class function with self-inner-product 1 that is not a character, so the claimed statement is refuted.

step 1.1step 1.2step 1.3discharge-construct: counterexample

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources