Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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FALSE: every crossed homomorphism is an ordinary homomorphism

Statement

Every crossed homomorphism is an ordinary homomorphism.

Facts & Assumptions

Given: The nontrivial element t of C2 acting on Z by tn=n.

[L1]

A crossed homomorphism satisfies z(gh)=z(g)+gz(h) for abelian coefficients (Crossed homomorphism for a G-group).

Refutation

technique · direct
1.1

Define z:C2Z by z(1)=0 and z(t)=1. Then z(t2)=z(1)=0=1+t1=z(t)+tz(t), so [L1] shows that z is a crossed homomorphism.

givenL1algebra
2.1

But z is not an ordinary homomorphism, because a homomorphism C2Z must send t to an element of order dividing 2, hence to 0, whereas z(t)=1. Therefore the claim is false.

L1step 1.1algebra

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources