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Inflation-restriction exact sequence in degree one

Statement

Let NG and let A be an abelian G-group. Then the sequence

0H1(G/N,AN)InfH1(G,A)ResH1(N,A)

is exact.

Facts & Assumptions

Given: A normal subgroup NG and an abelian G-group A.

[L1]

Restriction and inflation in degree one are given by the explicit cocycle formulas of Restriction, inflation, and the quotient conjugation action on first cohomology.

[L2]

The crossed-homomorphism model agrees with the inhomogeneous degree-one model (The inhomogeneous one-cocycle model agrees with crossed homomorphisms in degree one).

Proof

technique · direct
1.1

Inflation is injective. Suppose zˉ:G/NAN inflates to a principal crossed homomorphism ggaa on G. For nN, inflation gives 0=zˉ(N)=naa, so aAN. Therefore the same formula already defines a principal cocycle on G/N, and the class of zˉ is zero.

givenL1algebra
1.2

Conversely, let z:GA be a crossed homomorphism whose restriction to N is trivial in H1(N,A). Then there exists aA such that z(n)=naa for all nN. Replace z by the cohomologous cocycle z(g)=z(g)(gaa). Now zN=0.

L1L2choosealgebra
2.1

If zˉ:G/NAN is a cocycle, then its inflation vanishes on N because nN=N. Hence ResInf=0.

L1step 1.1algebra
2.2

If nN and gG, then z(ng)=z(n)+nz(g)=nz(g), while also z(ng)=z(g(g1ng))=z(g)+gz(g1ng)=z(g) because g1ngN and zN=0. Therefore nz(g)=z(g) for all nN, so z(g)AN. Also z(gn)=z(g)+gz(n)=z(g), so z is constant on cosets of N.

step 1.2algebra
3.1

Define zˉ:G/NAN by zˉ(gN)=z(g). Step 2.2 shows this is well defined, and the crossed-homomorphism identity for z implies that zˉ is a cocycle on G/N. By construction, inflating zˉ gives z, so the original class of z lies in the image of inflation. Hence kerRes=imInf.

L1step 2.2step 2.1
4.1

Steps 1.1, 2.1, and 3.1 prove exactness of the displayed sequence.

step 1.1step 2.1step 3.1

Depends on

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