Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Every cycle in a connected plane domain is null-homologous in that domain

Statement

False claim. Every complex chain which is a cycle with trace in a complex domain is null-homologous in that domain.

Facts & Assumptions

Given: The annulus A={z:12<z<2} and the contour C(t)=exp(it) on [0,2π], taken as the chain with the single term (1,C).

[L1]

A cycle Γ with trace in an open Ω is null-homologous in Ω when n(Γ,q)=0 for every qCΩ (Null-homologous cycles and homologous cycles in an open set).

[L2]

A complex domain is homologically simply connected when every cycle with trace in it is null-homologous in it (Homologically simply connected complex domains).

[L3]

The annulus {12<z<2} is a complex domain, and the unit circle C in it is a cycle with n(C,0)=1, so C is not null-homologous in that annulus (A connected plane domain that is not homologically simply connected).

[L4]

For aC, r>0 and kZ, the contour a+rexp(ikt) on [0,2π] is a closed complex contour with index k for za<r and 0 for za>r (A circle traversed k times has winding number k inside and 0 outside).

[L5]

If Γ is a cycle with trace in an open Ω, null-homologous in Ω, and f is holomorphic on Ω, then Γfdz=0 (Cauchy's theorem for a null-homologous cycle).

[L6]

For a positively oriented circle a+rexp(it) with r>0, (2πi)1γdz/(za)=1 (The normalized integral around a positively oriented circle centred at a is 1).

[L7]

A single closed contour with coefficient 1 is a cycle whose trace is that contour's trace (Complex chains, their traces, and cycles) and whose index is that contour's winding number (Integration over a complex chain and the index of a chain).

[L8]

Nonvanishing quotients of functions complex differentiable at a point are complex differentiable there (Linearity, product, reciprocal, and quotient rules for complex derivatives).

Refutation

technique · direct
1.1

By [L3] the annulus A is a complex domain and the chain C is a cycle with trace {z=1}A; by [L4] and [L7] its index at 0 is 1.

givenL3L4L7
2.1

The point 0 lies in CA, and step 1.1 gives n(C,0)=10, so [L1] denies that C is null-homologous in A; the claim is therefore false, and by [L2] it is exactly the claim that every complex domain is homologically simply connected.

step 1.1L1L2
3.1

The hypothesis is not removable from Cauchy's theorem either: f(z)=1/z is holomorphic on A by [L8], since 0A, and Cdz/z=2πi0 by [L6], so the conclusion of [L5] fails for this cycle in this domain.

step 2.1L5L6L8

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

64 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources