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False statementConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-07-31
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False: convolution defines an incidence algebra for every poset

Statement

For every poset PP and every commutative ring RR, the formula

(fg)(x,y)=xzyf(x,z)g(z,y)(f*g)(x,y)=\sum_{x\le z\le y}f(x,z)g(z,y)

defines a convolution operation on all functions on comparable pairs.

Facts & Assumptions

Given: A countably infinite set MM, two further elements ,\bot,\top, a nonzero commutative ring RR, and the poset P:={,}MP:=\{\bot,\top\}\cup M in which <m<\bot<m<\top for every mMm\in M and distinct elements of MM are incomparable.

[F1]

Incidence convolution is defined by a finite commutative-monoid sum over [x,y][x,y], under the hypothesis that the poset is locally finite (The incidence functions I(P,R)I(P,R) of a locally finite poset and their convolution).

[F2]

A partial order is reflexive, antisymmetric and transitive, and local finiteness means that every interval [x,y][x,y] is finite (Partial order and partially ordered set, Intervals in a poset; locally finite, lower-finite and upper-finite posets).

Refutation

technique · direct
1.1

The displayed relation on PP is reflexive, antisymmetric and transitive: the only strict comparisons are from \bot to a middle element, from a middle element to \top, and from \bot to \top. Thus PP is a poset.

givenF2
1.2

Its interval [,][\bot,\top] is all of PP and contains the countably infinite set MM, so it is infinite and PP is not locally finite.

givenF2
2.1

Let ff and gg be the constant-one functions on comparable pairs. At the endpoint, the proposed convolution asks for zP1R\sum_{z\in P}1_R, an infinite sum that is not supplied by the additive group or ring axioms and is not the finite sum in [F1].

step 1.2F1
3.1

Therefore the formula does not define convolution for every poset; local finiteness is a genuine well-definedness hypothesis.

step 1.2step 2.1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 34 results over 12 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources