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CounterexampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passverified 2026-08-04 (gpt-5.6-sol-codex-subscription)
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A poset with a bottom, a top and countably many incomparable middle elements has an infinite interval, so convolution of constant-one functions is not defined

Statement refuted

Convolution of incidence functions is defined on every poset, even without local finiteness (False: convolution defines an incidence algebra for every poset).

Facts & Assumptions

Given: A nonzero commutative ring RR, the set P:={,}(N×{m})P:=\{\bot,\top\}\cup(\mathbb N\times\{m\}), with all three pieces disjoint, and the relation in which <\bot<\top and <(n,m)<\bot<(n,m)<\top for every nNn\in\mathbb N, distinct middle elements are incomparable, and equality is allowed.

[F2]

A poset is locally finite exactly when every interval is finite (Intervals in a poset; locally finite, lower-finite and upper-finite posets).

[F3]

Incidence convolution is the finite ring sum (fg)(x,y)=z[x,y]f(x,z)g(z,y)(f*g)(x,y)=\sum_{z\in[x,y]}f(x,z)g(z,y); local finiteness is what makes this sum defined (The incidence functions I(P,R)I(P,R) of a locally finite poset and their convolution).

Counterexample

technique · direct
1.1

The relation is reflexive. Opposite inequalities force equality, so it is antisymmetric, and its only nontrivial two-step strict chains have the form <(n,m)<\bot<(n,m)<\top, whose endpoints are already comparable; thus it is transitive. Hence PP is a poset.

given
1.2

Every point of PP lies between \bot and \top, so [,]=P[\bot,\top]=P. It contains the countably infinite subset N×{m}\mathbb N\times\{m\}, hence is infinite and PP is not locally finite.

givenF1F2
2.1

For constant-one functions ff and gg, the formal endpoint value is (fg)(,)=zP1R(f*g)(\bot,\top)=\sum_{z\in P}1_R. This has one term for every natural-indexed middle point, in addition to the endpoints, and is not the finite ring sum required by convolution.

step 1.2F3
3.1

Thus the proposed convolution is not defined at (,)(\bot,\top), refuting the statement.

step 1.2step 2.1

Remarks

?(0;m)(1;m)(2;m)¢¢¢(n;m)¢¢¢>countablymanyincomparablemiddleelements[?;>]=Pisin¯nite

Depends on

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Sources