Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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FALSE: every cyclotomic polynomial has all coefficients in {1,0,1}

Statement

False claim. Every coefficient of every cyclotomic polynomial ΦnZ[t] lies in {1,0,1}.

The failure first appears at n=105: the coefficient of t7 in Φ105(t) is 2.

Facts & Assumptions

Given: The cyclotomic recursion dnΦd(t)=tn1 for n1 (The cyclotomic polynomials ΦnZ[t], defined by dnΦd=tn1).

[L1]

For every n1, Φn is a monic polynomial in Z[t] and the displayed divisor recursion holds (The recursion defines a unique monic ΦnZ[t], of degree φ(n)).

Refutation

technique · direct
1.1

Running the divisor recursion for n=105=357 and truncating modulo t8 gives Φ105(t)(1t3)(1t5)(1t7)1t1+t+t2t5t62t7(modt8). The first congruence is the defining recursion with every factor of degree at least 15 dropped modulo t8, and the second comes from expanding (1t)1=1+t+t2+t3+t4+t5+t6+t7(modt8).

givenL1algebra
2.1

Step 1.1 shows that the coefficient of t7 in Φ105(t) is 2, and 2{1,0,1}. So the false claim fails.

step 1.1algebra

Remarks

  • Why this is a real pattern and not a silly claim. For many small values of n the coefficients do lie in {1,0,1}, so the first counterexample is not visually obvious from the recursion alone.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources