Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedprecheck passaudited 2026-08-26
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FALSE: every cyclotomic polynomial has all coefficients in {−1,0,1}

Statement

False claim. Every coefficient of every cyclotomic polynomial Φn∈Z[t] lies in {−1,0,1}.

The failure first appears at n=105: the coefficient of t7 in Φ105(t) is −2.

Facts & Assumptions

Given: The cyclotomic recursion ∏d∣nΦd(t)=tn−1 for n≥1 (The cyclotomic polynomials Φn∈Z[t], defined by ∏d∣nΦd=tn−1).

[L1]

For every n≥1, Φn is a monic polynomial in Z[t] and the displayed divisor recursion holds (The recursion defines a unique monic Φn∈Z[t], of degree φ(n)).

Refutation

technique · direct
1.1givenL1algebra

Running the divisor recursion for n=105=3⋅5⋅7 and truncating modulo t8 gives Φ105(t)≡(1−t3)(1−t5)(1−t7)1−t≡1+t+t2−t5−t6−2t7(modt8). The first congruence is the defining recursion with every factor of degree at least 15 dropped modulo t8, and the second comes from expanding (1−t)−1=1+t+t2+t3+t4+t5+t6+t7(modt8).

2.1step 1.1algebra∎

Step 1.1 shows that the coefficient of t7 in Φ105(t) is −2, and −2∉{−1,0,1}. So the false claim fails.

Remarks

  • Why this is a real pattern and not a silly claim. For many small values of n the coefficients do lie in {−1,0,1}, so the first counterexample is not visually obvious from the recursion alone.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources