Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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FALSE: Φn is irreducible over every field

Statement

False claim. For every field K and every n1 with the characteristic of K not dividing n, the image of Φn in K[t] is irreducible.

What is true is different in two directions: over Q every Φn is irreducible, but over a finite field the factor degree is governed by the order of the Frobenius class modulo n.

Facts & Assumptions

Given: The rational irreducibility theorem and the finite-field factorisation theorem.

[L1]

For every n1, the cyclotomic polynomial Φn is irreducible in Q[t] (Φn is irreducible in Q[t] for every n1).

[L2]

If gcd(n,q)=1, the reduction of Φn in Fq[t] is a product of distinct monic irreducibles, each of degree the order of [q] modulo n (For gcd(n,q)=1 the reduction of Φn in Fq[t] is a product of distinct monic irreducibles, each of degree the order of [q] modulo n).

Refutation

technique · direct
1.1

In (Z/5)× one has [11]=[1], so the order of [11] modulo 5 is 1. Therefore [L2] says that over F11 every irreducible factor of Φ5 has degree 1.

L2algebra
2.1

Hence the reduction of Φ5 in F11[t] is a product of distinct linear factors, so it is reducible there. This contradicts the false claim.

step 1.1algebra
3.1

The contradiction does not touch [L1]: irreducibility over Q is a theorem, but it does not persist over arbitrary base fields.

step 2.1L1

Remarks

  • The finite-field theorem is the correct replacement. The question over Fq is not "irreducible or not?" in the abstract, but "what is the order of [q] modulo n?"

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

32 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources