Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-09-01
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FALSE: the degree-zero horseshoe lift is unique

Statement

False. Once the side resolutions and the short exact sequence are fixed, the lift s:P0′′→A of the right augmentation through the middle epimorphism in the degree-zero horseshoe step is unique.

Facts & Assumptions

Given: The split short exact sequence 0⟶Z→x↦(x,0)Z⊕Z→(x,y)↦yZ⟶0, with each end object resolved by its length-zero identity resolution.

[L1]

The degree-zero horseshoe construction chooses a lift of the right augmentation through the middle epimorphism (The degree-zero horseshoe lift).

Refutation

technique · direct
1.1givenalgebra

Let p(x,y)=y. The identity augmentation Z→Z lifts through p both by s1(y)=(0,y) and by s2(y)=(y,y), since ps1=ps2=id⁡Z. The induced degree-zero middle augmentations are respectively λ1(x,y)=(x,y) and λ2(x,y)=(x+y,y).

2.1L1step 1.1∎

By step 1.1, both maps satisfy the lifting equation required in [L1], but s1(1)=(0,1)≠(1,1)=s2(1). Thus the degree-zero horseshoe lift is not unique.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources