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False statementConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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FALSE: every torsion-free module over a PID is free

Statement

False claim. Every torsion-free module over a principal ideal domain is free, without a finite-generation hypothesis.

Facts & Assumptions

Given: The rational field Q (The rationals form a field), bases and free modules (Generated submodule, cyclic and finitely generated modules, module basis and free module), the integer ring and cancellation law (The integers form a commutative ring, The integers have no zero divisors; multiplicative cancellation), the fact that every additive subgroup of Z is cyclic (Every subgroup of (Z,+) is n=nZ for exactly one natural number n), the PID definition (Principal ideal domain), and the valid finitely generated theorem Every finitely generated torsion-free module over a PID is free. These integer facts show that Z is a PID.

[F1]

A module is torsion-free when its torsion subset is {0} (Annihilators, torsion elements and the torsion subset of a module).

Refutation

technique · contradiction
1.1

Under the usual integer action, Q is a Z-module. If nq=0 with n0, field cancellation gives q=0, so it is torsion-free by [F1].

F1algebra
2.1

Suppose, for contradiction, that Q has a Z-basis B. It cannot be empty because Q0, so choose bB. Express b/2 as a finite integer linear combination of basis elements and multiply by 2. Uniqueness of basis coordinates would make the coefficient of b simultaneously 1 and an even integer, which is impossible.

step 1.1assume-contrachoosealgebra
3.1

Step 2.1 rules out every nonempty basis, and the empty basis cannot span the nonzero module. Thus Q is torsion-free over the PID Z but is not free; finite generation is essential.

step 2.1discharge-contradiction

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

43 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources