Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passverified 2026-08-03 (gpt-5.6-sol-codex-subscription)
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The integers form a commutative ring

Statement

(Z,+,,0,1)(\mathbb{Z}, +, \cdot, 0, 1) with the operations of Arithmetic on the integers is a commutative ring with multiplicative identity, in which every element has the additive inverse [(a,b)]=[(b,a)]-[(a,b)] = [(b,a)].

Facts & Assumptions

Given: Z\mathbb{Z} with the operations of Arithmetic on the integers.

[L1]

Addition on N\mathbb{N} is commutative and associative, with zero as a two-sided identity (Addition is commutative, Addition is associative, Left identity for addition).

[L2]

Multiplication on N\mathbb{N} is commutative and associative, distributes over addition, and has the usual zero and identity laws (Multiplication is commutative, Multiplication is associative, Distributivity and the successor law for multiplication, Zero and one under multiplication).

[L3]

The integer operations are independent of representatives (Integer addition and negation are well defined, Integer multiplication is well defined).

Proof

technique · direct
1.1

By [L3], each axiom may be verified on arbitrary fixed representatives (a,b),(c,d),(e,f)(a,b), (c,d), (e,f).

L3suffices
1.2

Associativity of ++: ((a,b)+(c,d))+(e,f)((a,b)+(c,d))+(e,f) and (a,b)+((c,d)+(e,f))(a,b)+((c,d)+(e,f)) both equal (a+c+e,  b+d+f)(a+c+e,\; b+d+f).

L1
1.3

Commutativity of ++: (a+c,b+d)=(c+a,d+b)(a+c,\, b+d) = (c+a,\, d+b).

L1
1.4

Additive identity: (a,b)+(0,0)=(a+0,b+0)=(a,b)(a,b) + (0,0) = (a+0,\, b+0) = (a,b).

L1
1.5

Additive inverses: (a,b)+(b,a)=(a+b,b+a)(0,0)(a,b) + (b,a) = (a+b,\, b+a) \sim (0,0), since (a+b)+0=(b+a)+0(a+b) + 0 = (b+a) + 0.

L1
1.6

Commutativity of \cdot: swapping (a,b)(c,d)(a,b) \leftrightarrow (c,d) sends (ac+bd,ad+bc)(ac+bd,\, ad+bc) to (ca+db,cb+da)(ca+db,\, cb+da), the same pair.

L1L2
1.7

Multiplicative identity: (a,b)(1,0)=(a1+b0,  a0+b1)=(a,b)(a,b) \cdot (1,0) = (a \cdot 1 + b \cdot 0,\; a \cdot 0 + b \cdot 1) = (a,b).

L1L2
1.8

Associativity of \cdot: expanding, both ((a,b)(c,d))(e,f)((a,b)(c,d))(e,f) and (a,b)((c,d)(e,f))(a,b)((c,d)(e,f)) equal (ace+adf+bcf+bde,  acf+ade+bce+bdf)(ace+adf+bcf+bde,\; acf+ade+bce+bdf).

L1L2
1.9

Distributivity: (a,b)((c,d)+(e,f))=(a(c+e)+b(d+f),  a(d+f)+b(c+e))=(ac+bd,ad+bc)+(ae+bf,af+be)=(a,b)(c,d)+(a,b)(e,f)(a,b) \cdot ((c,d)+(e,f)) = (a(c+e)+b(d+f),\; a(d+f)+b(c+e)) = (ac+bd,\, ad+bc) + (ae+bf,\, af+be) = (a,b)(c,d) + (a,b)(e,f).

L1L2
2.1

Steps 1.2–1.9 verify all axioms: (Z,+,,0,1)(\mathbb{Z}, +, \cdot, 0, 1) is a commutative ring with identity and additive inverses.

step 1.1step 1.2step 1.3step 1.4step 1.5step 1.6step 1.7step 1.8step 1.9

Depends on

Used by

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