Alphabeta Math
DefinitionDefinition: Literature-sourcedProof: Not applicableSession-authored (Fable 5 assisted)audited 2026-07-24
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Arithmetic on the integers

Definition

On Z\mathbb{Z} (The integers as equivalence classes of pairs of naturals) define, on representatives,

[(a,b)]+[(c,d)]:=[(a+c,  b+d)],[(a,b)] + [(c,d)] := [(a+c,\; b+d)], [(a,b)][(c,d)]:=[(ac+bd,  ad+bc)],[(a,b)] \cdot [(c,d)] := [(ac+bd,\; ad+bc)], [(a,b)]:=[(b,a)],0:=[(0,0)],1:=[(1,0)].-[(a,b)] := [(b,a)], \qquad 0 := [(0,0)], \qquad 1 := [(1,0)].

These do not depend on the chosen representatives (Integer addition and negation are well defined , Integer multiplication is well defined ).

Remarks

  • The product formula is forced by the intended meaning: if (a,b)(a,b) stands for aba-b and (c,d)(c,d) for cdc-d, then (ab)(cd)=(ac+bd)(ad+bc)(a-b)(c-d) = (ac+bd) - (ad+bc).
  • Negation swaps the components: (ab)=ba-(a-b) = b-a.

Depends on

Used by

…and 44 more results.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 14 results over 9 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources