Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (z-ai/glm-5.2)audited 2026-07-28
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.

12Z+18Z=6Z and 12Z∩18Z=36Z, the arithmetic of gcd⁡ and lcm⁡ read off the subgroups of (Z,+)

Example

Take a=12 and b=18. Then gcd⁡(12,18)=6 and lcm⁡(12,18)=36, and aZ+bZ=gcd⁡(a,b) Z and aZ∩bZ=lcm⁡(a,b) Z; equivalently, in (Z,+) the subgroup generated by {a,b} is ⟨gcd⁡(a,b)⟩ and ⟨a⟩∩⟨b⟩=⟨lcm⁡(a,b)⟩ turns these two numbers into two statements about subgroups of (Z,+):

12Z+18Z  =  6Z,12Z∩18Z  =  36Z.

The first says that the integers expressible as 12x+18y are exactly the multiples of 6; the smallest positive one is 6=12⋅(−1)+18⋅1. The second says that the integers divisible by both 12 and 18 are exactly the multiples of 36. The product check is gcd⁡⋅lcm⁡=6⋅36=216=∣12⋅18∣.

Numerals. For k∈N the symbol k inside Z means ι(k), the embedding of The naturals embed in the integers.

Facts & Assumptions

Given: The integers 12, 18, 6, 36 and 216, and gZ={ gk:k∈Z }.

[L1]

Z is a commutative ring: multiplication is associative and commutative, x⋅1=x, x⋅(−1)=−x, and multiplication distributes over addition (The integers form a commutative ring, Arithmetic on the integers, The integers as equivalence classes of pairs of naturals).

[L6]

If xz=yz and z≠0 then x=y (The integers have no zero divisors; multiplicative cancellation).

[L8]

Every subgroup of (Z,+) has exactly one nonnegative generator (Every subgroup of (Z,+) is ⟨n⟩=nZ for exactly one natural number n).

Verification

technique · direct
1.1

gcd⁡(12,18)=6. Indeed 6≥0; 12=6⋅2 and 18=6⋅3, so 6∣12 and 6∣18; and 12⋅(−1)+18⋅1=−12+18=6, so every common divisor of 12 and 18 divides 6 by [L3]. By [L2] this characterises gcd⁡(12,18).

L1L2L3algebra
2.1

lcm⁡(12,18)=36. By [L4], gcd⁡(12,18)lcm⁡(12,18)=∣12⋅18∣=∣216∣=216; with step 1.1 this reads 6⋅lcm⁡(12,18)=216. Since 6⋅36=216 and 6≠0, cancellation gives lcm⁡(12,18)=36.

step 1.1L1L4L5L6algebra
3.1

Applying [L7] with a=12 and b=18: 12Z+18Z=gcd⁡(12,18)Z=6Z and 12Z∩18Z=lcm⁡(12,18)Z=36Z.

step 1.1step 2.1L7
4.1

Both right-hand sides are written with their canonical generator: 6≥0 and 36≥0, and by [L8] no other nonnegative integer generates the same subgroup, so the two identities pin the subgroups down rather than merely exhibiting one description of each.

step 3.1L8
5.1

The two statements read concretely: an integer is of the form 12x+18y exactly when it is a multiple of 6 — with 6=12⋅(−1)+18⋅1 the smallest positive such value — and an integer is divisible by both 12 and 18 exactly when it is a multiple of 36, which is the divisibility clause of [L4] instantiated here.

step 1.1step 3.1L3L4∎

Remarks

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