Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (z-ai/glm-5.2)audited 2026-07-28
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.

12Z+18Z=6Z and 12Z∩18Z=36Z, the arithmetic of gcd⁡ and lcm⁡ read off the subgroups of (Z,+)

Example

Take a=12 and b=18. Then gcd⁡(12,18)=6 and lcm⁡(12,18)=36, and aZ+bZ=gcd⁡(a,b) Z and aZ∩bZ=lcm⁡(a,b) Z; equivalently, in (Z,+) the subgroup generated by {a,b} is ⟨gcd⁡(a,b)⟩ and ⟨a⟩∩⟨b⟩=⟨lcm⁡(a,b)⟩ turns these two numbers into two statements about subgroups of (Z,+):

12Z+18Z  =  6Z,12Z∩18Z  =  36Z.

The first says that the integers expressible as 12x+18y are exactly the multiples of 6; the smallest positive one is 6=12⋅(−1)+18⋅1. The second says that the integers divisible by both 12 and 18 are exactly the multiples of 36. The product check is gcd⁡⋅lcm⁡=6⋅36=216=∣12⋅18∣.

Numerals. For k∈N the symbol k inside Z means ι(k), the embedding of The naturals embed in the integers.

Facts & Assumptions

Given: The integers 12, 18, 6, 36 and 216, and gZ={ gk:k∈Z }.

[L1]

Z is a commutative ring: multiplication is associative and commutative, x⋅1=x, x⋅(−1)=−x, and multiplication distributes over addition (The integers form a commutative ring, Arithmetic on the integers, The integers as equivalence classes of pairs of naturals).

[L6]

If xz=yz and z≠0 then x=y (The integers have no zero divisors; multiplicative cancellation).

[L8]

Every subgroup of (Z,+) has exactly one nonnegative generator (Every subgroup of (Z,+) is ⟨n⟩=nZ for exactly one natural number n).

Verification

technique · direct
1.1L1L2L3algebra

gcd⁡(12,18)=6. Indeed 6≥0; 12=6⋅2 and 18=6⋅3, so 6∣12 and 6∣18; and 12⋅(−1)+18⋅1=−12+18=6, so every common divisor of 12 and 18 divides 6 by [L3]. By [L2] this characterises gcd⁡(12,18).

2.1step 1.1L1L4L5L6algebra

lcm⁡(12,18)=36. By [L4], gcd⁡(12,18)lcm⁡(12,18)=∣12⋅18∣=∣216∣=216; with step 1.1 this reads 6⋅lcm⁡(12,18)=216. Since 6⋅36=216 and 6≠0, cancellation gives lcm⁡(12,18)=36.

3.1step 1.1step 2.1L7

Applying [L7] with a=12 and b=18: 12Z+18Z=gcd⁡(12,18)Z=6Z and 12Z∩18Z=lcm⁡(12,18)Z=36Z.

4.1step 3.1L8

Both right-hand sides are written with their canonical generator: 6≥0 and 36≥0, and by [L8] no other nonnegative integer generates the same subgroup, so the two identities pin the subgroups down rather than merely exhibiting one description of each.

5.1step 1.1step 3.1L3L4∎

The two statements read concretely: an integer is of the form 12x+18y exactly when it is a multiple of 6 — with 6=12⋅(−1)+18⋅1 the smallest positive such value — and an integer is divisible by both 12 and 18 exactly when it is a multiple of 36, which is the divisibility clause of [L4] instantiated here.

Remarks

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