The naturals embed in the integers

Depends on

• The integers as equivalence classes of pairs of naturals
• Arithmetic on the integers
• Order on the integers
• The natural numbers $\mathbb{N}$ (von Neumann)
• Order on the natural numbers
• Left identity for addition
• Zero and one under multiplication
• $\le$ is a linear order on $\mathbb{N}$

Used by

• A finite group of prime order is cyclic and every nonidentity element generates it Corollary
• A rational root of xᵏ = m is an integer: if k ≥ 1, m ∈ ℤ, x ∈ ℚ and xᵏ is the image of m, then x is the image of an integer Corollary
• Every nonzero integer n is u ∏_i<r pᵢ with u ∈ {1,-1} and every pᵢ prime; u and r are determined by n, and the list is determined up to a permutation Corollary
• For an integer p > 1: p is prime if and only if, for all integers a and b, p ∣ ab implies p ∣ a or p ∣ b Corollary
• g^|G|=e for every element g of a finite group G Corollary
• If a prime p divides a finite product ∏_i<n aᵢ of integers then p ∣ aᵢ for some i < n; at n = 0 the product is 1 and the hypothesis cannot hold Corollary
• n+1 divides C(2n, n) for every n∈ℕ Corollary
• Positive integers 4ᵃ m with m≡ 7 (mod 8) need four nonzero squares Corollary
• The order of every element of a finite group divides the order of the group Corollary
• 2ℤ is closed under addition, negation and multiplication and is not a subring of ℤ, because it does not contain 1 Counterexample
• 6 ∣ 4 · 9 while 6 ∤ 4 and 6 ∤ 9: dividing a product does not force dividing a factor, and the coprimality hypothesis is what fails Counterexample
• A nonempty subset of a group closed under the operation need not be a subgroup: the nonnegative integers inside (ℤ, +) Counterexample
• If 1 were admitted as a prime, uniqueness would fail: 6 = 2 · 3 = 1 · 2 · 3 = 1 · 1 · 2 · 3, lists of different lengths that no permutation matches Counterexample
• In the multiplicative monoid H = {1, 4, 7, 10, …} of positive integers one more than a multiple of 3, the element 100 has two genuinely different factorisations into irreducibles, 4 · 25 and 10 · 10 Counterexample
• The common divisors of (0,0) are all of ℤ and have no greatest element in the order of ℤ, so gcd(0,0) cannot be defined as a maximum and is fixed by convention Counterexample
• The map n ↦ (n,0) from ℤ to ℤ × ℤ preserves addition and multiplication and does not preserve 1, so the clause f(1) = 1 is not redundant Counterexample
• ℤ and {n + 1/n : n ≥ 2} are disjoint closed subsets of ℝ at distance 0, so the set-to-set distance is not a metric Counterexample
• ψ(1/x) has no limit at 0: two sequences tending to 0 give values constantly 0 and constantly 1/2 Counterexample
• Combinatorial classes, counting sequences and ordinary generating functions Definition
• Common multiple, and the least common multiple lcm(a,b), taken to be 0 when a = 0 or b = 0 Definition
• Complete quotients in the continued-fraction algorithm Definition
• Integer powers aᵐ Definition
• Integer powers in the complex field Definition
• Lattice paths, step sets and step words Definition
• Powers gⁿ: natural exponents in a monoid and integer exponents in a group, with g⁰ = e Definition
• Prime and composite integers: p is prime when p > 1 and its only positive divisors are 1 and p Definition
• Rational powers aʳ of a positive base Definition
• The Catalan generating function C(x)=∑_n≥0Cₙxⁿ in ℚ⟦ x⟧ Definition
• The Dirichlet function 1_ℚ, and Thomae's function t with t(x) = 1/q at a rational x = p/q in lowest terms with q ≥ 1 and t(x) = 0 at every irrational x Definition
• The p-adic valuation vₚ(a) of a nonzero integer: the greatest k ∈ ℕ with pᵏ ∣ a Definition
• (ℤ, +) is an abelian group, (ℤ, ·) is a commutative monoid that is not a group, and its group of units is {1, -1} Example
• 12ℤ + 18ℤ = 6ℤ and 12ℤ ∩ 18ℤ = 36ℤ, the arithmetic of gcd and lcm read off the subgroups of (ℤ,+) Example
• 2 is prime, and it is the only even prime: every even integer n > 2 is composite Example
• 360 = 2³ · 3² · 5 and 84 = 2² · 3 · 7, with gcd(360,84) = 12 and lcm(360,84) = 2520 read off the exponents Example
• ax + by = c has an integer solution exactly when gcd(a,b) ∣ c: 6x + 15y = 9 is solvable and 6x + 15y = 7 is not Example
• Bézout coefficients are not unique: 1071 · (-3) + 462 · 7 = 21 and 1071 · 19 + 462 · (-44) = 21, and for nonzero a, b every solution has the form (x₀ + t b/d, y₀ - t a/d) Example
• Ceiling ⊣ inclusion ⊣ floor: an adjoint triple between (ℝ,≤) and (ℤ,≤) Example
• Consecutive Fibonacci numbers are coprime, and for every m ∈ ℕ the Euclidean algorithm on (Fₘ₊₃, Fₘ₊₂) takes exactly m+1 divisions, with quotient 1 in the first m of them and quotient 2 in the last Example
• Eisenstein proves xⁿ-2 irreducible over ℚ for every positive n Example
• Every positive divisor of the order of a finite cyclic group occurs as the order of a subgroup Example

…and 68 more results.

Dependency tree · two levels

22 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources

• T. Tao, Analysis I, 3rd ed., §4.1 (standard reference, not scraped)
• Integer — construction from pairs of naturals (Wikipedia) (standard reference, not scraped)