Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: Literature-sourcedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-28
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

22 is prime, and it is the only even prime: every even integer n>2n > 2 is composite

Example

Call an integer even when 2n2 \mid n (Divisibility in Z\mathbb{Z}: dad \mid a when a=dqa = dq for some integer qq), where 2:=1+12 := 1 + 1. Then:

  1. 22 is prime (Prime and composite integers: pp is prime when p>1p > 1 and its only positive divisors are 11 and pp);
  2. every even integer n>2n > 2 is composite.

So 22 is the only even prime, and every other prime is odd.

Facts & Assumptions

Given: The integer 2:=1+12 := 1 + 1.

[L1]

pp is prime when p>1p > 1 and every positive divisor of pp is 11 or pp; an integer n>1n > 1 that is not prime is composite (Prime and composite integers: pp is prime when p>1p > 1 and its only positive divisors are 11 and pp).

[L5]

The order on Z\mathbb{Z} is total, antisymmetric and transitive and is compatible with addition (The integers form a totally ordered ring, Order on the integers); Z\mathbb{Z} is a commutative ring (The integers form a commutative ring, Arithmetic on the integers, The integers as equivalence classes of pairs of naturals).

[L6]

ι:NZ\iota : \mathbb{N} \to \mathbb{Z} is injective, preserves addition and order, and has as image exactly the nonnegative integers, with ι(0)=0\iota(0) = 0 and ι(1)=1\iota(1) = 1 (The naturals embed in the integers).

[L7]

On N\mathbb{N}: m<km < k exactly when σ(m)k\sigma(m) \le k (Discreteness: σ(n)\sigma(n) is the immediate successor); 1=σ(0)1 = \sigma(0) (The natural numbers N\mathbb{N} (von Neumann)); 0k0 \le k for every kk (Order on the natural numbers).

Verification

technique · direct
1.1

0<10 < 1: 1=ι(1)1 = \iota(1) is nonnegative and differs from 0=ι(0)0 = \iota(0) by injectivity of ι\iota. Adding 11 gives 1<1+1=21 < 1 + 1 = 2, so 2>1>02 > 1 > 0.

L5L6
1.2

There is no integer strictly between 00 and 11: if 0<x0 < x then x=ι(j)x = \iota(j) with j0j \ne 0, so 1=σ(0)j1 = \sigma(0) \le j and hence 1x1 \le x, because ι\iota preserves the order.

L6L7
2.1

Claim 1. Let dd be a positive divisor of 22. Since 202 \ne 0, [L2] gives d2=2|d| \le |2| = 2, and d>0d > 0 gives d=d|d| = d, so 1d21 \le d \le 2 by step 1.2.

step 1.1step 1.2L2L3L5
2.2

Claim 2. Let n>2n > 2 with 2n2 \mid n. Then n>2>1n > 2 > 1, so n>1n > 1; and 22 is a positive divisor of nn with 212 \ne 1 (by step 1.1) and 2n2 \ne n (since n>2n > 2).

step 1.1L5
3.1

The only integers dd with 1d21 \le d \le 2 are 11 and 22: if d1d \ne 1 then 1<d1 < d, so 1+1d1 + 1 \le d by step 1.2 applied to d1>0d - 1 > 0, that is 2d2 \le d, and with d2d \le 2 antisymmetry gives d=2d = 2. Both 11 and 22 do divide 22. Hence the only positive divisors of 22 are 11 and 22, and 2>12 > 1, so 22 is prime.

step 1.1step 1.2step 2.1L1L4L5
3.2

So nn has a positive divisor other than 11 and nn, hence is not prime; being greater than 11, it is composite.

step 2.2L1
4.1

Claims 1 and 2 are established, and together they say 22 is the only even prime: an even prime nn satisfies n>1n > 1, hence 2n2 \le n by step 3.1's argument, and n>2n > 2 is excluded because such an nn is composite by step 3.2; so n=2n = 2.

step 1.2step 3.1step 3.2L1L5

Remarks

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 65 results over 24 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources