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Every connected covering of the circle is regular
Statement
Every connected covering of is regular, including the universal cover and the one-sheeted cover.
Facts & Assumptions
Given: A connected covering .
For a covering with path-connected total space and path-connected locally path-connected base, regularity is equivalent to normality of the induced subgroup in the base fundamental group (A connected covering is regular exactly when its induced subgroup is normal, exactly when deck transformations act transitively on a fibre).
Degree gives an isomorphism from the circle fundamental group to ( is an isomorphism).
Every subgroup of an abelian group is normal (Every subgroup of an abelian group is normal).
The additive group of is abelian (The integers form a commutative ring).
The quotient circle is path-connected ( is compact and path-connected).
Open quotient arcs are homeomorphic to convex real intervals and form arbitrarily small path-connected neighbourhoods of circle points, so the quotient circle is locally path-connected (The quotient map is open, and every interval shorter than one embeds in , Every nonempty convex subset of is simply connected, Locally connected and locally path-connected spaces: a neighbourhood base of open connected, respectively open path-connected, sets at every point).
Local path-connectedness lifts from the base of a covering to its total space (Local path-connectedness lifts and descends along covering maps).
A connected locally path-connected space is path-connected (A connected, locally path-connected space is path-connected, because its path components are open).
Proof
By [F4] and [F5], the base is path-connected and locally path-connected. Since the covering total space is connected, [F6] and [F7] make it path-connected. By [F1] and [F3], its induced subgroup corresponds to a subgroup of an abelian group, so [F2] makes it normal.
Applying [L1] to step 1.1 shows that the covering is regular.
Depends on
- A connected covering is regular exactly when its induced subgroup is normal, exactly when deck transformations act transitively on a fibre
- $\operatorname{Deg}:\pi_1(\mathbb R/\mathbb Z,[0])\to(\mathbb Z,+)$ is an isomorphism
- Every subgroup of an abelian group is normal
- The integers form a commutative ring
- $\mathbb R/\mathbb Z$ is compact and path-connected
- The quotient map is open, and every interval shorter than one embeds in $\mathbb R/\mathbb Z$
- Every nonempty convex subset of $\mathbb R^n$ is simply connected
- Locally connected and locally path-connected spaces: a neighbourhood base of open connected, respectively open path-connected, sets at every point
- Local path-connectedness lifts and descends along covering maps
- A connected, locally path-connected space is path-connected, because its path components are open
Used by
Dependency tree · two levels
57 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Allen Hatcher, Algebraic Topology, Proposition 1.39 (standard reference, not scraped)