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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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Deg:π1(R/Z,[0])(Z,+) is an isomorphism

Statement

Deg:π1(R/Z,[0])(Z,+) is an isomorphism. Its inverse is

n[ωn].

Facts & Assumptions

Given: The degree function on based loop classes of the quotient circle.

[L1]

Deg:π1(S1,[0])(Z,+) is a group homomorphism (Deg:π1(S1,[0])(Z,+) is a group homomorphism).

[L2]

Two based circle loops are path-homotopic if and only if they have equal degree (Two based circle loops are path-homotopic if and only if they have equal degree).

[L3]

deg(ωn)=n for every integer n (deg(ωn)=n for every integer n).

[L4]

An isomorphism f:GH is a bijective group homomorphism (Group isomorphisms, automorphisms and the set Aut(G)).

[L5]

The integers form a commutative ring, and hence (Z,+) is a group (The integers form a commutative ring).

[L6]

π1(X,x0) consists of endpoint-fixed path-homotopy classes [α] of based loops (Based loops and the fundamental group).

Proof

technique · direct
1.1

By [L1], Deg is a group homomorphism into the additive group of integers supplied by [L5].

L1L5
1.2

If Deg([α])=Deg([β]), then deg(α)=deg(β), so [L2] makes α and β path-homotopic. Their classes are equal by [L6], and Deg is injective.

L2L6
1.3

Let nZ. By [L3], Deg([ωn])=deg(ωn)=n, so every integer is attained and Deg is surjective. This includes n=0, n=1, and negative integers.

L3
2.1

Steps 1.1, 1.2, and 1.3 show that Deg is a bijective group homomorphism, hence an isomorphism by [L4]. Step 1.3 also shows that n[ωn] is its inverse, since injectivity makes this preimage unique.

step 1.1step 1.2step 1.3L3L4

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 64 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources