Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-21
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Connected coverings of the circle are classified by the subgroups nZ for n0

Statement

For each nN, let nZ be the subgroup of (Z,+) generated by n. Connected coverings of R/Z, up to based isomorphism or up to unbased isomorphism, are in bijection with the nonnegative integers through the subgroup

nZπ1(R/Z,[0])Z.

For n1 the corresponding covering has n sheets. The case n=0 is the infinite-sheeted universal covering RR/Z, and n=1 is the one-sheeted covering.

Facts & Assumptions

Given: The quotient circle based at [0].

[L1]

Based connected coverings correspond to subgroups of the base fundamental group, while unbased connected coverings correspond to conjugacy classes of subgroups (Connected covering spaces are classified by conjugacy classes of fundamental-group subgroups).

[L2]

The quotient projection RR/Z is a universal covering (RR/Z is a universal covering).

[F1]

Degree gives an isomorphism π1(R/Z,[0])(Z,+) (Deg:π1(R/Z,[0])(Z,+) is an isomorphism).

[F2]

Every subgroup of (Z,+) is nZ for exactly one natural number n (Every subgroup of (Z,+) is n=nZ for exactly one natural number n).

[F3]

For a covering with nonempty path-connected total space, the number of sheets is the index of its induced subgroup, with both finite or both infinite (For a nonempty path-connected total space, a covering fibre is in bijection with the right cosets of the induced fundamental-group subgroup).

[F4]

The additive group of Z is abelian (The integers form a commutative ring).

[F5]

The quotient group (Z,+)/nZ has the same coset set as Z/n (For every nN, the congruence-class group (Z/n,+) is the quotient group (Z,+)/nZ).

[F6]
[F7]

The quotient circle is nonempty and path-connected (R/Z is compact and path-connected).

[F8]

The quotient map is open, and every real interval of length below one maps homeomorphically to its image in the quotient circle (The quotient map is open, and every interval shorter than one embeds in R/Z).

[F9]

Every nonempty convex interval is simply connected (Every nonempty convex subset of Rn is simply connected).

[F10]

Local path-connectedness requires arbitrarily small open path-connected neighbourhoods, while semilocal simple connectedness requires a neighbourhood whose inclusion induces the trivial fundamental-group map (Locally connected and locally path-connected spaces: a neighbourhood base of open connected, respectively open path-connected, sets at every point, Semilocally simply connected spaces with explicit basepoint convention).

[F11]

A pointed homeomorphism induces a fundamental-group isomorphism (Induced fundamental-group maps are well defined, functorial and invariant under based homotopy).

[F12]

Local path-connectedness lifts from the base of a covering to its total space (Local path-connectedness lifts and descends along covering maps).

[F13]

Proof

technique · direct
1.1

Let [a] be a circle point and let N be an open neighbourhood of it. The inverse image of N is open and contains a, so it contains an interval J about a of length below one. By [F8], p[J] is an open neighbourhood of [a] inside N and is homeomorphic to the convex interval J. Thus [F9], [F10], and [F11] show that the circle is locally path-connected and semilocally simply connected; [F7] supplies nonemptiness and path-connectedness. The classification theorem [L1] therefore applies. Transporting its subgroups through [F1], [F2] says that every induced subgroup is uniquely nZ for one nN.

L1F1F2F7F8F9F10F11
2.1

By [L1], this gives one based-isomorphism class for each n. Since [F4] makes every conjugate of nZ equal to itself, the same parameter gives the unbased-isomorphism classes. Conversely, [L1] realizes every nZ, so both correspondences are bijections.

step 1.1L1F4
3.1

Every classified covering has connected total space. Since step 1.1 establishes that the circle is locally path-connected, [F12] and [F13] make each such total space path-connected, licensing [F3]. For n1, [F5] and [F6] give [Z:nZ]=n, so [F3] gives n sheets. For n=0, the subgroup is trivial, [F5] and [F6] give infinite index, and [L2] realizes this class by the real-line universal cover. At n=1 the index is one.

step 1.1step 2.1L2F3F5F6F12F13

Depends on

Used by

Dependency tree · two levels

95 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources