Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedprecheck passaudited 2026-09-01
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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FALSE: translation is continuous in L

Statement

False claim. Translation is continuous in L(Rn).

Facts & Assumptions

Given: The indicator of the unit interval in one dimension.

Refutation

technique · direct
1.1

Let f:=1[0,1] on R. For every h0, the [L1, given, algebra] functions f and τhf differ by 1 on a set of positive measure: for 0<h<1, for instance, on (1,1+h] one has τhf=1 and f=0.

L1givenalgebra
2.1

Therefore [step 1.1, algebra]

τhff=1

for every h0, so the norm does not tend to 0 as h0.

step 1.1algebra
3.1

Hence translation is not continuous in L, which is exactly why [L1, step 2.1] [L1] stops at p<.

L1step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources