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A product collar deformation retracts onto its face

Statement

Let M be a smooth manifold (possibly with boundary) and let C=M×[0,1] be a product collar with face M0=M×{0} (the restriction of a smooth collar, Smooth collars of a manifold boundary). Then the projection r:C→M0,r(x,t):=(x,0), is a strong deformation retraction (Retractions and deformation retracts, with a deformation retraction required to fix the retract pointwise), and consequently for every abelian group G and every i the relative homology Hi(C,M0;G) vanishes: the map of pairs r:(C,M0)→(M0,M0) induces isomorphisms on relative homology (Relative singular homology).

Facts & Assumptions

Given: A smooth manifold M, the product collar C=M×[0,1] with face M0=M×{0}, and an abelian group G.

[F1]

A strong deformation retraction of X onto A⊆X is a retraction r:X→A together with a homotopy H:id⁡X≃Ai∘r fixing A pointwise (Retractions and deformation retracts, with a deformation retraction required to fix the retract pointwise).

[F2]

A map f:X→Y is a homotopy equivalence when there is g:Y→X with g∘f≃id⁡X and f∘g≃id⁡Y (Homotopy equivalences, homotopy inverses and spaces of the same homotopy type).

[L1]

A homotopy equivalence induces an isomorphism on singular homology in every degree and every coefficient group (Homotopy equivalences induce isomorphisms on singular homology).

[F3]

For A⊆X the sequence ⋯→Hn(A;G)→Hn(X;G)→Hn(X,A;G)→δHn−1(A;G)→⋯ is exact (Long exact sequence of a pair).

[F4]

A map of pairs induces a commuting morphism of the two pair long exact sequences, including the connecting maps (Naturality of the pair long exact sequence).

[F5]

If four comparison maps of a morphism of long exact sequences in an abelian category are isomorphisms, then so is the fifth (Five lemma for a morphism of long exact sequences).

[L2]

The relative chain group is Cn(X,A;G)=Cn(X;G)/Cn(A;G), so Cn(X,X;G)=0 and Hn(X,X;G)=0 for all n (Relative singular chain complex, Relative singular homology).

Proof

technique · explicit formulas
1.1F1givenconstruct

Define H((x,t),s):=(x,(1−s)t) for (x,t)∈C and s∈[0,1]. This is continuous, being the restriction of the smooth map M×[0,1]2→C, and it satisfies H((x,t),0)=(x,t), H((x,t),1)=(x,0)=r(x,t) and H((x,0),s)=(x,0) for every (x,t)∈C and every s. Thus r is a retraction of C onto M0 and H is a homotopy from id⁡C to i∘r fixing M0 pointwise, so by [F1] the projection r is a strong deformation retraction onto M0.

2.1F2L1step 1.1

Since r∘i=id⁡M0 and H displays i∘r≃id⁡C, the maps r and the inclusion i:M0→C are homotopy inverses, so r is a homotopy equivalence by [F2]. By [L1], for every j the induced map Hj(r;G):Hj(C;G)→Hj(M0;G) is an isomorphism.

3.1F3F4step 2.1

The map r is a map of pairs r:(C,M0)→(M0,M0), so by [F4] it induces a morphism from the exact sequence of [F3] for (C,M0) to that for (M0,M0): ⋯→Hj(M0;G)→Hj(C;G)→Hj(C,M0;G)→Hj−1(M0;G)→⋯ compared with ⋯→Hj(M0;G)→Hj(M0;G)→Hj(M0,M0;G)→Hj−1(M0;G)→⋯ . In this morphism the comparison map on Hj(C;G) is the isomorphism of step 2.1, and every comparison map on a copy of Hj(M0;G) is the identity, because on the subspace M0 the map r is the identity.

4.1F5step 3.1

Fix i and apply [F5] to the five-term window of this morphism centred on the comparison map Hi(C,M0;G)→Hi(M0,M0;G): by step 3.1 the four surrounding comparison maps are isomorphisms (each is either an identity or Hj(r;G)), so the relative comparison map is an isomorphism.

5.1L2step 4.1∎

The relative complex of the pair (M0,M0) is the zero complex by [L2], so Hi(M0,M0;G)=0; hence Hi(C,M0;G)=0 for every i, and the map of pairs r induces these isomorphisms on relative homology.

Remarks

  • The general collar case. A smooth collar neighbourhood of ∂M is diffeomorphic to a product (Smooth collars of a manifold boundary), so the lemma applies to it verbatim; this is the form used to identify the relative homology of the top sublevel pair in the relative Morse inequalities.
  • Choice. The homotopy H and the retraction r are explicit formulas, so no choice principle is used to define the deformation; the cited homological suppliers are used as published.
  • Empty cases. If M=∅ then C=∅=M0 and all groups vanish; the argument applies with H the empty map.

Depends on

Used by

Dependency tree · two levels

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Sources