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A negative-gradient trajectory on a compact Morse manifold has single critical alpha and omega limits
Statement
Let be compact, let be Morse, and let be a negative-gradient trajectory. Then is full and there are critical points and such that
Facts & Assumptions
Given: A compact smooth manifold , a Morse function , and a negative-gradient trajectory .
A smooth vector field on a compact manifold is complete (Every smooth vector field on a compact manifold is complete).
Precompact full tails have nonempty compact connected invariant limit sets (Precompact trajectory tails have nonempty compact connected flow-invariant limit sets).
Such limit sets for a negative-gradient trajectory consist of critical points (Every precompact end-limit point of a negative-gradient trajectory is critical).
A Morse function on a compact manifold has finitely many critical points (A Morse function on a compact manifold has finitely many critical points).
Proof
By [F1], the negative-gradient field is complete, so has domain . Both tails have compact closure because they lie in .
By [F2] each of and is nonempty and connected, and [F3] places it in .
By [F4], is finite and hence discrete. A connected subset of a discrete finite set is one point, so both limit sets are single critical points.
A trajectory with singleton tail-limit set converges to that point: otherwise a sequence of tail times outside a fixed neighbourhood would have a limit point in the same tail-limit set. Thus the two displayed limits hold.
Depends on
Used by
Dependency tree · two levels
15 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Ralph L. Cohen, Bundles, Manifolds, and Homotopy, Theorem 13.2 (standard reference, not scraped)