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A non-closed leaf of a codimension-one foliation meets a closed transversal

Statement

Assume ACω (The countable-choice principle used in the foliation pair). Let F be a smooth cooriented codimension-one foliation of a smooth manifold M, and let A be a leaf that is not a closed subset of M. There is a smooth embedded circle transverse to F that meets A.

The circle need not lie in every prescribed open neighborhood of A; the localization claim is false. The stronger finite-compact-barrier version needed in compact ambient manifolds is constructed directly in the global closedness lemma.

Facts & Assumptions

Given: The smooth foliation, coorientation and nonclosed leaf A of the statement.

[F1]

Foliation boxes have plaques at fixed transverse coordinates, and transverse coordinates change only as functions of the old transverse coordinate (Regular foliation atlases).

[F2]

Points on a leaf can be joined by finite plaque chains and hence by compact leafwise paths (Leaves of a regular foliation).

[F3]

Coorientation consistently orders transversals and makes plaque transports increasing (Transversely oriented codimension-one foliations).

Proof

1.1F1F2F3choose

Choose x∈A‾∖A and a product box centered at x. Infinitely many distinct plaques of A meet smaller boxes about x; otherwise their finitely many transverse levels could not accumulate at the level of x without including its plaque. Thus a short vertical segment T meets A twice. Join two such intersections by a compact embedded leafwise arc using F2 and removal of loops. Its intersections with T are finite: they are closed in the compact arc and locally isolated by foliation boxes. Taking consecutive intersections along this arc gives a subarc whose interior misses T. Orient it from its higher endpoint to its lower endpoint.

2.1F1F3step 1.1construct

Cover this compact arc by finitely many foliation boxes. Compose their plaque transports to obtain a thin foliated strip with central arc coordinate u=0 and positive transverse coordinate u; the transverse direction is consistent by F3. On this strip tilt the arc from u=−ε to u=ε with strictly positive derivative in u. Choose ε small enough that its final endpoint is still below its initial endpoint on T. Close it by the positive vertical segment between those endpoints. The central arc meets T only at its endpoints, so a sufficiently thin strip and sufficiently small endpoint modifications make the closed curve embedded. It crosses A where u=0, and every segment is positively transverse. Smooth the two corners inside product boxes. Convexity of the positive transverse tangent half-space preserves transversality, and a sufficiently small modification preserves embedding and the interior crossing of A.

3.1step 2.1∎

The resulting curve is the required smooth embedded transverse circle meeting A. The construction uses finitely many boxes, one compact arc and finitely many shrinkings. It makes no arbitrary-neighborhood localization assertion.

Localization counterexample

On R×S1, with angle θ in radians modulo 2π, take the smooth foliation tangent to ∂θ−r∂r. The leaf A={(e−t,t mod 2π):t∈R} is nonclosed and accumulates on r=0. On r>0 the circle-valued function Φ=θ+log⁡r mod 2π is a first integral. For 0<ε<π, the open set U=Φ−1((−ε,ε)) contains all of A, and Φ lifts on U to a real-valued smooth submersion. Along a closed transverse curve in U, the derivative of this real-valued first integral would be continuous and nowhere zero, hence have a constant sign, which is impossible for a periodic real function. Thus U contains no closed transverse curve at all. Removing the localization clause preserves the actual source theorem and the global finite-barrier proof route.

Depends on

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Sources