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Fibres of abelian schemes and unit-preserving morphisms

Statement

Assume AC and DC. Let S be a scheme, let A→S and B→S be abelian schemes of relative dimensions gA,gB (Abelian schemes over a base), and let s∈S. Then:

(a) the fibre As is an abelian variety of dimension gA over κ(s);

(b) the multiplication of A is commutative and the inversion is the morphism −1A:A→A;

(c) every S-morphism u:A→B with u∘eA=eB is a homomorphism of S-group schemes;

(d) consequently, on a connected base, any two abelian-scheme group structures on the same smooth proper S-scheme with the same unit section coincide.

Facts & Assumptions

Given: AC and DC, abelian schemes A→S, B→S and a point s∈S.

[F1]

An abelian scheme has smooth proper connected geometric fibres of constant dimension (Abelian schemes over a base); the fibre over s is the base change to κ(s) (Scheme-theoretic fibre, Field-valued points and local-ring points).

[F2]

Every abelian variety over a field is commutative, and a pointed morphism from a smooth geometrically integral group variety to an abelian variety is a homomorphism (A proper geometrically connected group variety is commutative, Pointed morphisms from smooth geometrically integral groups to abelian varieties are homomorphisms, Abelian varieties over a field).

[F3]

A morphism of abelian schemes over S which is constant on every geometric fibre factors through the base (Fibrewise constant morphisms from an abelian scheme factor through the base).

Proof

technique · direct: the field-level statements applied fibrewise, then the rigidity factorization to pass to morphisms
1.1F1givenalgebra

The fibre As=A×SSpec⁡κ(s) is smooth, proper and geometrically connected of dimension gA over κ(s) by [F1], hence an abelian variety of dimension gA; this is (a).

2.1F2F3step 1.1algebra

For commutativity, let c:A×SA→A be the commutator morphism c(a,b)=aba−1b−1, using the group law; it sends the unit sections to the unit. For each geometric point tˉ of the base, the fibre of A×SA→S over tˉ is Atˉ×tˉAtˉ, and by the field-level commutativity [F2] the commutator is constant, equal to the identity, on each geometric fibre of the second projection; by [F3] applied to the base change AA→A (second projection), c factors through the base, and evaluating at the first unit section gives c=1, hence ab=ba as morphisms. This proves the first claim of (b), including nilpotents.

3.1F1step 2.1algebra

For the inverse: m(id⁡A,−1A) and e∘f agree on the closed subscheme A by the group axioms, so the inverse is −1A as defined; this is the second claim of (b).

4.1F2F3step 2.1algebra∎

For (c), let u:A→B satisfy u∘eA=eB and consider the defect morphism d(a,b)=u(a+b)−u(a)−u(b) on A×SA, using the group law of B. On each geometric fibre of the first projection, the field-level pointed-morphism theorem [F2] makes d constant, equal to 0; by [F3] it factors through the base and evaluation at a=eA gives d≡0, so u is additive; compatibility with the unit is assumed, so u is a homomorphism of S-group schemes. For (d), two group structures on the same S-scheme with the same unit section have an identity morphism which preserves the unit, hence is a homomorphism by (c), and being an isomorphism of underlying schemes it identifies the two structures.

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