Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Adjacent-window divided-difference recurrence

Statement

Let n∈N, n≥1, and d∈N with d<n; let x0<⋯<xn be real nodes, let x∈R be distinct from these nodes, and let f:{x0,…,xn,x}→R. For every 0≤i≤n−d, put Gi:=f[xi,…,xi+d,x]. Then, for every 0≤i<n−d, Gi−Gi+1=−(xi+d+1−xi)f[xi,…,xi+d+1,x].

Facts & Assumptions

Given: n∈N, n≥1, d∈N with d<n, ordered distinct real nodes x0,…,xn, an additional distinct real point x, and real-valued data f on these points.

[F1]

Divided differences on distinct nodes: the divided difference satisfies the recursive endpoint rule.

[F2]

Divided differences are symmetric leading coefficients: divided differences are symmetric in all listed nodes.

[F3]

The natural numbers N (von Neumann): N contains 0 and is closed under successor, so d+2∈N.

Proof

1.1F1F2F3algebra

Apply the recursive endpoint rule [F1] to the order-(d+2) divided difference on the ordered endpoints xi,xi+d+1 and the intermediate list xi+1,…,xi+d,x. Symmetry [F2] identifies its two numerator terms as Gi+1 and Gi, respectively, so f[xi,…,xi+d+1,x]=Gi+1−Gixi+d+1−xi.

2.1givenstep 1.1algebra∎

The denominator in step 1.1 is positive because the nodes are strictly ordered. Rearranging that identity gives the stated identity.

Depends on

Used by

Dependency tree · two levels

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Sources