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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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Affine central coroot from the transpose null ray

Statement

For an indecomposable affine GCM A in the row-coroot convention αj(hi)=aij, there is a unique positive integer vector b=(bi) with Atb=0 and gcd⁡ibi=1. The element cA=∑ibihi is nonzero, central in g(A) and belongs to its derived algebra. On any cyclic highest-weight module of weight λ, it acts by the scalar λ(cA). This scalar defines the intrinsic GCM level; no loop-model normalization is included in this assertion.

Facts & Assumptions

Given: An indecomposable affine GCM with its minimal realization.

[F1]

Affine A and At have rank n−1 and unique positive null rays (Finite affine indefinite trichotomy for indecomposable gcms).

[F2]

The coroots hi are independent and αj(hi)=aij (Realization of a generalized cartan matrix).

[F3]

The generators satisfy [h,ej]=αj(h)ej, [h,fj]=−αj(h)fj, [ei,fi]=hi and commuting Cartan relations (Contragredient lie algebra before the maximal ideal quotient).

[F4]

These generators descend to g(A) and the Cartan embeds (Kac moody algebra associated to a gcm).

Proof

1.1F1given

Row reduction of the integer matrix At uses rational operations. Its rank over Q equals its rank over R, since the same nonzero minors determine rank. Thus its rational kernel has dimension one: choose the one free coordinate to be 1 and solve the pivot equations to obtain a nonzero rational null vector. Its real span is the real kernel by F1. Since that kernel contains a strictly positive vector, all its coordinates have one strict sign; change the sign if necessary. Multiply by the product of the finitely many positive denominators to get a positive integer null vector, then divide its entries by their positive gcd to obtain b. If b′ is another such primitive positive vector, the common null line gives b′=qb with positive rational q. Write q=r/s in lowest positive integer terms. Since every rbi/s is integral and r,s are coprime, s divides every bi, hence s=1. Primitivity of b′ then forces r=1. This proves uniqueness.

2.1F2F3F4step 1.1

Independence and the embedded Cartan in F2 and F4 make cA≠0. For every j, F2 and F3 give [cA,ej]=(∑ibiaij)ej=(Atb)jej=0 and [cA,fj]=−(Atb)jfj=0. It also commutes with every Cartan element. The identity [cA,[x,y]]=[[cA,x],y]+[x,[cA,y]] propagates these equalities through all Lie words in the generators, proving centrality. Moreover cA=∑ibi[ei,fi] by F3, so it belongs to [g,g].

3.1F3F4step 2.1∎

On a highest vector v of weight λ, the Cartan action gives cAv=λ(cA)v. By 2.1, commuting cA through any finite enveloping word u gives cAuv=ucAv=λ(cA)uv. Such vectors span the cyclic module, proving scalar action. Positive normalization rules out b=0, whereas level zero is permitted. A single affine index cannot occur since the one-by-one GCM [2] has no null vector; no empty-index case is hidden in the indecomposable affine hypothesis. The rational elimination, denominator clearing and gcd operations are finite and require no AC.

Depends on

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Sources