Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
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Vanishing aggregate-model error controls the proximal candidate

Statement

Let F:Rn→(−∞,+∞] be proper, closed, and convex, with nonempty closed convex domain C=dom⁡F. Fix t>0, a center x∈C, and a finite affine model M≤F on C. Let z minimize M(y)+∥y−x∥22/(2t) over C, set e=F(z)−M(z)≥0, and let p=prox⁡tF(x). Then ∥z−p∥22≤4te. In particular, a sequence of such model errors ek→0 forces the model candidates to approach their exact proximal points in norm.

Facts & Assumptions

[F1]

p is the unique minimizer of QF(y)=F(y)+∥y−x∥22/(2t) (Proximal mapping, Existence, resolvent characterization, and firm nonexpansiveness of the proximal map).

[F2]

The convex function QF obeys QF(z)≥QF(p)+∥z−p∥22/(4t) (A quadratic regularization has quadratic growth from its minimizer).

Proof

1.1givenF1algebra

Put QM(y)=M(y)+∥y−x∥22/(2t). Since z minimizes QM over C and p∈C, QM(z)≤QM(p). The pointwise underestimator gives QM(p)≤QF(p), while QF(z)=QM(z)+e. Hence QF(z)≤QF(p)+e.

2.1F2step 1.1algebra∎

Apply [F2] to z and combine with step 1.1: QF(p)+∥z−p∥22/(4t)≤QF(z)≤QF(p)+e. Subtracting the common finite value and multiplying by 4t>0 proves the inequality.

Depends on

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Dependency tree · two levels

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Sources