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Limits of approximate margin-KKT points under MFCQ
Statement
Let and let be locally Lipschitz. Let be feasible for and satisfy MFCQ in the margin convention. Suppose that for every there is a feasible with and multipliers/subgradients witnessing that is an -approximate Clarke KKT point. Then is a Clarke KKT point.
Statement references
Facts & Assumptions
Given: Locally Lipschitz margins, a feasible point satisfying MFCQ, and for every tolerance a nearby feasible approximate KKT witness with stationarity and complementarity errors no larger than that tolerance.
Clarke subdifferential and gradient-flow trajectory: Clarke subdifferentials are compact, locally bounded, and have closed graph; for fixed , their support function is upper semicontinuous in .
KKT conditions and MFCQ for margin constraints: approximate KKT supplies nonnegative multipliers, subgradients, and the two error bounds; exact KKT is the corresponding zero-error stationarity and complementary-slackness condition.
For a nonempty subset of with , compactness, closedness and boundedness, pseudocompactness, and attainment of extrema by every continuous real-valued function are equivalent: closed bounded subsets of finite-dimensional Euclidean space are compact.
Proof
Let . If , every constraint has positive slack near . Local boundedness in [F1] gives a common bound on all nearby subgradients. For any sufficiently small , the approximate witness in [F2] satisfies for positive local slack bounds , so its stationarity residual gives . This holds for every small , hence ; setting all exact multipliers to zero gives KKT.
Suppose . By MFCQ choose and let be a common lower bound for over active and ; such a bound exists by compactness and finiteness. Then for each active . Upper semicontinuity in [F1] gives a neighborhood where every active subgradient satisfies . Shrink it so each inactive constraint has slack at least and all subgradients are bounded by . For any sufficiently small , the approximate witness has for inactive . Dotting its stationarity equation with therefore bounds the sum of active multipliers by . Thus, for all sufficiently small , all multipliers and subgradients in every witness are uniformly bounded.
Choose an integer large enough that every approximate witness with for lies in a fixed closed bounded box of the finite-dimensional space of parameters, multipliers, and subgradients, using step 1.2. For each , let consist of feasible witnesses with , stationarity residual at most , and aggregate complementarity residual at most . The hypothesis makes every nonempty; continuity and the closed-graph property in [F1] make it closed. Hence each is compact by [F3], and .
The nested family has the finite-intersection property, since every finite intersection equals its largest-index member. Compactness of therefore makes nonempty. Any tuple in this intersection has , zero stationarity residual, and zero complementarity residual, because each corresponding norm/error is at most for every . It is consequently an exact Clarke KKT witness by [F2]. This argument selects one point from one nonempty intersection and uses no choice principle.
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Sources
- Kaifeng Lyu and Jian Li, Gradient Descent Maximizes the Margin of Homogeneous Neural Networks, Appendix C.1, Theorem C.4 (standard reference, not scraped)
- Matus Telgarsky, Deep Learning Theory lecture notes, §9.1 (standard reference, not scraped)