Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-09-27
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Čech H0 equals global sections

Statement

Let X be a topological space, F a sheaf of abelian groups on X, and U=(Ui)i∈I an open cover of X indexed by a linearly ordered set, with fixed-cover Čech cohomology Hˇ∙(U,F) (Fixed-cover Čech cohomology). Then restriction of global sections, Γ(X,F)⟶Hˇ0(U,F),s⟼(s∣Ui)i∈I, is an isomorphism, and it is natural in F: for a morphism φ:F→G of abelian sheaves the square Γ(X,F)⟶Hˇ0(U,F)↓Γ(X,φ)↓Hˇ0(U,φ)Γ(X,G)⟶Hˇ0(U,G) commutes.

Facts & Assumptions

[F1]

C0(U,F)=∏i∈IF(Ui) and (δ0s)ij=sj∣Ui∩Uj−si∣Ui∩Uj for i<j (Ordered Čech cochain complex of a cover).

[F2]

A sheaf satisfies locality: if s,t∈F(X) have s∣Ui=t∣Ui for all i in a cover, then s=t; and gluing: compatible sections si∈F(Ui) with si∣Ui∩Uj=sj∣Ui∩Uj have a section restricting to each si (A sheaf on a topological space).

[F3]

Hˇ0(U,F)=ker⁡(δ0)/im⁡(δ−1)=ker⁡(δ0), since C−1(U,F)=0 (Fixed-cover Čech cohomology).

[F4]

Γ(X,F)=F(X) and Γ(X,φ)=φX, and a morphism of sheaves commutes with restrictions (Global sections of an abelian sheaf, Sections, restrictions, and global sections of a presheaf).

[F5]

A section over the empty open set is zero, F(∅)=0 (A set-valued sheaf has a unique section over the empty open set); in particular for the empty space and empty cover the product over no indices is the zero group.

Proof

Given: A topological space X, a sheaf of abelian groups F and an ordered open cover U of X.

1.1

Define Φ:Γ(X,F)→C0(U,F)=∏i∈IF(Ui) by Φ(s):=(s∣Ui)i∈I [F1, F4]. For s∈Γ(X,F) and i<j one has (δ0Φ(s))ij=s∣Uj∣Ui∩Uj−s∣Ui∣Ui∩Uj=s∣Ui∩Uj−s∣Ui∩Uj=0 by compatibility of restrictions [F1, F4], so Φ takes values in ker⁡(δ0); it is a group homomorphism because restrictions are homomorphisms.

F1F4
2.1

Φ is injective: if Φ(s)=0 then s∣Ui=0 for every i, and since the Ui cover X the locality half of the sheaf condition [F2] gives s=0.

F2step 1.1
2.2

Φ is surjective onto ker⁡(δ0): let (si)i∈I∈ker⁡(δ0). For i<j the equation (δ0s)ij=0 reads sj∣Ui∩Uj=si∣Ui∩Uj [F1], so the family is compatible on all pairwise intersections and the gluing half of the sheaf condition [F2] produces s∈F(X) with s∣Ui=si for all i; then Φ(s)=(si) by [step 1.1] and this section is unique by locality. (If some Ui is empty its component group is 0 by [F5], so the corresponding entry is forced to be zero and imposes no condition.) [F1, F2, F5, step 1.1]

F1F2F5
3.1

Hence Φ is an isomorphism of abelian groups from Γ(X,F) onto ker⁡(δ0), and by [F3] the latter is Hˇ0(U,F); so the displayed restriction map is an isomorphism. For naturality, let φ:F→G be a morphism of abelian sheaves. Since φ commutes with restrictions [F4], for every s∈Γ(X,F) and every i one has φUi(s∣Ui)=φX(s)∣Ui, so ΦG(φX(s))=C0(U,φ)(ΦF(s)); as Hˇ0(U,φ) is the map induced on ker⁡(δ0) [F1, F3], the square commutes and the isomorphism is natural in F. [F3, F4, step 2.2] ∎

F3F4∎

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