Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-29
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Chart independence of Cr smoothness

Statement

Let M and N be smooth manifolds, let F:M→N be continuous at p∈M, and let r∈N0∪{∞}. Let (U,φ), (U′,φ′) be smooth charts of M at p and (V,ψ), (V′,ψ′) smooth charts of N at F(p), with F(U)⊆V and F(U′)⊆V′. If the representative ψ∘F∘φ−1 is of class Cr on a neighbourhood of φ(p), then the representative ψ′∘F∘φ′−1 is of class Cr on a neighbourhood of φ′(p). Testing one chart pair therefore agrees with testing any other.

Facts & Assumptions

Given: The manifolds, map, point, smoothness class r, and the four charts of the Statement, with ψ∘F∘φ−1 of class Cr near φ(p).

[F1]

Any two charts of a smooth manifold are smoothly compatible: their domains are disjoint or both transition maps are smooth (Smoothly compatible charts and the smoothness of Euclidean transition maps, Smooth manifolds and their smooth charts).

[L1]

If u:W→W′ is smooth and g:W′→W′′ is Cr, then g∘u is Cr; and if h:W→W′ is Cr and v:W′→W′′ is smooth, then v∘h is Cr (Compatibility of smooth atlases is an equivalence relation, and smooth Euclidean maps compose).

Proof

technique · direct
1.1givenF1

The overlaps U∩U′ and V∩V′ contain p and F(p), so both are [given, F1] nonempty; by [F1] the transitions φ∘φ′−1 on φ′(U∩U′) and ψ′∘ψ−1 on ψ(V∩V′) are smooth. Because F is continuous at p and F(p)∈V∩V′, there is an open neighbourhood Up⊆U∩U′ of p with F(Up)⊆V∩V′.

2.1givenF1L1step 1.1

On φ′(Up) the new representative factors as

ψ′∘F∘φ′−1=(ψ′∘ψ−1)∘(ψ∘F∘φ−1)∘(φ∘φ′−1).

First [L1] composes the smooth φ∘φ′−1 after the Cr map ψ∘F∘φ−1 and keeps Cr; then [L1] composes the smooth ψ′∘ψ−1 after that and keeps Cr. The middle factor is Cr on the image of φ′(Up) under φ∘φ′−1, which is an open neighbourhood of φ(p) inside the set where the given representative is Cr; hence the composite is Cr on φ′(Up). [given, F1, L1, step 1.1]

3.1givenstep 2.1∎

The set φ′(Up) is an open neighbourhood of φ′(p), so the [given, step 2.1] representative ψ′∘F∘φ′−1 is Cr near φ′(p). The reverse implication is the same argument with the chart pairs interchanged.

Depends on

Used by

Cited to discharge well-definedness by Cʳ and smooth maps between smooth manifolds.

Dependency tree · two levels

17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources