Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Polarized relations in a Clifford algebra

Statement

Let k,V,B,Q be as in Universal Clifford algebra of a quadratic space, and let vˉ=iQ(v). Then

vˉwˉ+wˉvˉ=2B(v,w)1

for all v,w∈V.

Facts & Assumptions

Given: A field k of characteristic not 2, a finite-dimensional k-vector space V, a symmetric bilinear form B, Q(v)=B(v,v), and v,w∈V.

[F1]

The quotient map sends each v∈V to an element satisfying iQ(v)2=Q(v)1 (Universal Clifford algebra of a quadratic space).

Proof

technique · direct
1.1givenF1algebra

Applying [F1] to v+w, v, and w, then subtracting the last two defining equalities from the first, gives vˉwˉ+wˉvˉ=(Q(v+w)−Q(v)−Q(w))1.

2.1givenstep 1.1algebra∎

Bilinearity and symmetry give Q(v+w)−Q(v)−Q(w)=B(v,w)+B(w,v)=2B(v,w), proving the relation.

Depends on

Used by

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources