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Commuting affine peripheral holonomies factor their logarithms on singular parameter spaces

Statement

Let Z be a reduced complex analytic space with point o, and suppose ui,vi,ai,bi are holomorphic germs on Z for 1≤i≤k, with k<∞, ui(o)=vi(o)=0, ai(o)≠0 and τi0=bi(o)/ai(o)∉R. Suppose the affine maps Li(w)=euiw+ai,Pi(w)=eviw+bi commute at every parameter point. Then, after shrinking around o, there are holomorphic germs τi such that vi=τiui, τi(o)=τi0 and Im⁡τi≠0 throughout. In particular ui=0 if and only if vi=0, and vi/ui→τi0 as the parameter tends to o through ui≠0. No smoothness, dimension or rank hypothesis on Z is required.

For ui≠0, there is a unique real pair (pi,qi) solving piui+qivi=2πi. With u~i=2πipi+τi0qi, one has ∣u~i−ui∣≤∣τi−τi0∣∣Im⁡τi0∣∣ui∣. Set u~i=0 when ui=0. The functions u~i are continuous at such points, and ∥u~−u∥=o(∥u∥) as the parameter tends to o through u≠0.

Facts & Assumptions

Given: The finite collection of holomorphic germs, their values at o and the commuting affine maps in the Statement.

Proof

1.1givenconstructalgebra

If k=0, the collection of germs and every indexed assertion are empty. Both vectors are the unique vector of C0, with norm zero; there is no parameter with u≠0, so the final limiting assertion is vacuous. This proves the Statement in that case. Henceforth suppose k≥1. Composition of the two affine maps shows that commutativity is exactly ai(evi−1)=bi(eui−1). Let E(t)=(et−1)/t for t≠0 and E(0)=1; its convergent series is ∑n≥0tn/(n+1)!, so it is holomorphic and nonzero near zero. Since ai(o)≠0, the holomorphic function τi=(bi/ai)E(ui)/E(vi) is defined near o. The commutativity equation becomes exactly vi=τiui, and τi(o)=bi(o)/ai(o). The finitely many nonreal values permit one common neighborhood on which all Im⁡τi are nonzero. Thus all τi are nonzero, proving the equivalence of their zero logarithms and the asserted quotient limit. The argument is an identity of holomorphic functions on Z, so singular points cause no difficulty.

2.1step 1.1algebra

When ui≠0, real linear independence of ui and vi=τiui follows from Im⁡τi≠0. Hence the real linear map (p,q)↦pui+qvi is invertible and gives the unique real pair. Its equation is (pi+qiτi)ui=2πi. Since Im⁡τi0≠0, the denominator pi+qiτi0 cannot vanish: if it did, its imaginary part would give qi=0, then its real part pi=0, contrary to the full-turn equation. Therefore u~i/ui=(pi+qiτi)/(pi+qiτi0) and (u~i−ui)/ui=qi(τi−τi0)/(pi+qiτi0). The elementary bound ∣pi+qiτi0∣≥∣qi∣ ∣Im⁡τi0∣ proves the estimate, including qi=0 where its left side is zero.

3.1step 1.1step 2.1algebra∎

On a sufficiently small fixed neighborhood all τi are bounded, so step 2.1 gives ∣u~i∣≤C∣ui∣. Thus extending u~i by zero across ui=0 is continuous there; elsewhere its formula is continuous because it comes from an invertible real linear system. Put η(z)=max⁡i∣τi(z)−τi0∣/∣Im⁡τi0∣. Finiteness of k and continuity give η(z)→0 as z→o. Applying the scalar estimates coordinatewise, also where ui=0, gives ∥u~−u∥≤η(z)∥u∥. This proves the final assertion. No claim that u is a coordinate system or has nonvanishing derivative has entered the argument.

Scope

The affine normalization retains a chosen peripheral fixed point or eigenline. This lemma supplies the logarithmic quotient and the filling-parameter comparison even when the shape space is singular. It supplies neither a holomorphic coordinate on an ordinary character quotient nor the analytic-space openness, isolated-complete-point, geometric realization or triangulation-existence prerequisites needed for general hyperbolic Dehn filling.

Used by

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